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anonymous

  • 5 years ago

hey can anybody solve this question .... if f(x)=x2-x,show that f(x+1)=f(-x)

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  1. anonymous
    • 5 years ago
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    f(x+1) = (x+1)^2 - (x+1) = x^2 +2x +1 - x -1 =x^2 +x = f(-x)

  2. anonymous
    • 5 years ago
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    f(x+1)=(x+1)^2 -(x+1) = (x+1)((x+1-1) = x(x-1)=f(x)...ur statement is wrong..maybe??

  3. anonymous
    • 5 years ago
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    hey thanx mate

  4. anonymous
    • 5 years ago
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    but iam still blank :S

  5. anonymous
    • 5 years ago
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    nah ive checked it statement is right

  6. anonymous
    • 5 years ago
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    ankur \[f(x)\neq x(x-1)\]

  7. anonymous
    • 5 years ago
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    err nvm, durr

  8. radar
    • 5 years ago
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    \[f(x)=x ^{2}-x\] This was given Show that f(x+1) = f(-x). Work out each one and see if it is true First do f(x+1)\[f(x+1)=(x+1)^{2}-(x+1)=x ^{2}+2x+1-x-1=x ^{2}+x\] Now work it out for -x \[f(-x)=(-x)^{2}-(-x)=x ^{2}+x\] The results look the same to me

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