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i'm pretty sure you typed the question wrong, velocity should be a function of time so it should be v = 12 sqrt (t)
integrate the function, we'll call the new function s
s(t) = 8t^(3/2) + C
plug in t = 0, which would make for the function
s(0) = 8t^(3/2) + C
1 = C
so s(t) = 8t^(3/2) + 1
s(1) = 8*1(3/2) + 1
s(1) = 9
I thought the same thing at first, but I copied it exactly the way it is.
The answer has to be 49
hmm....is there anything else to the question?
i'm sorry for asking this, but it's hard to see velocity as a function of distance.. you usually see it as a function of time
and i don't know how you're supposed to integrate that then, what would be the new function?
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nope, that's all its written.
I am thinking that parametric equations is the key.
But the question is too specific for me to look it up.
I'm sorry, i can't help you
even if we integrate with respect to s it wouldnt matter
because s is 0
so constant would be very small.
plugging 0 OR 1 would give you a small number
49 is a huge number...
sorry, but good luck