anonymous
  • anonymous
Find the vertex and all intercepts of the parabola. Then sketch and determine window values. The problem is: f(x)=-x^2-2x+3
Mathematics
katieb
  • katieb
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
the formula to find the mim/max point of a parabola is \[x=-\frac{b}{2a}\] so \[x = \frac{2}{-2} = -1\] so y = 4 so the vertex is (-1, 4) to find the intercepts just set x and y equal to 0 one by one the equation is y = -x^2 - 2x + 3 y = 0 0 = -x^2 - 2x + 3 x^2 + 2x -3 = 0 (x - 1)(x + 3) = 0 x = 1, -3 so the x intercepts are (1, 0) and (-3, 0) x = 0 y = 3 y intercept is (0, 3)

Looking for something else?

Not the answer you are looking for? Search for more explanations.