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anonymous
 5 years ago
whats the definite integral from pi/6 to pi/4 of x/(1x^4)^1/2
anonymous
 5 years ago
whats the definite integral from pi/6 to pi/4 of x/(1x^4)^1/2

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You cannot do this by hand because letting u=1x^4 its derivative would equate 4x^3 dx, which cannot be substituted into the equation. To find the result, type in the equation into y= on your calculator. Then go 2ND>Calc (top row of buttons) and hit #7 for integration. It will graph the function, and then ask for a lower and upper bound which is obviously the limits you provided.

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.2did you try a trig substitution? that might work

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that's not true, it's a identity it's the inverse sin identity.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thats what i'm supposed to do, but i'm extremely lost. What do you mean it's the inverse sin identity?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\frac{1}{2}\sin^{1} (x^2)dx\] from pi/6 to pi/4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you can derive it, but most teachers (even in college) do not require it most teachers don't even require you to know them but some want you to memorize them that's the only way to recognize them that integral is the derivative of the inverse sin function

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oh god lol I feel like a dolt. Yes it's an inverse trig ID. Sorry

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0whoa myininaya, did you just do that? lols props!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i dont think we're there yet. we're supposed to substitute and let u=x^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then how are you going to integrate the u^2 without a u on the outside...

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.2they are not hard to derive. it is harder for me to memorize more stuff so i derive it everytime

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i dont know, thats why im so confused

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0myininaya the hint that came with the question said to let u=x^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it's going to get really messy...but you can try u  subbing again....

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.2why let u=x^2 when you can let cos( pheta)=x^2

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.2where is the hint you guys are talking about? don't do that way. lol. hints can be gross

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0LOLOLOLOLL go myininaya

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.2i mean we can try, but I don't see why

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its number 2 on the first page

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.2have you done trig substitution before?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.2ok let me think about then

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok, thanks for helping me with this

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i think i understand what your book wants it want's u sub and trig id give me a min to type this out

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{\pi/6}^{\pi/4}\frac{x}{\sqrt{1x^4}}dx\] substitute u = x^2 and du = 2xdx \[\frac{1}{2}\int\limits_{}^{}\frac{1}{\sqrt{1u^2}}du\] now you use the trig id \[\int\limits_{}^{}\frac{1}{\sqrt{1u^2}} = \sin^{1} (u)\] so the answer is \[\frac{1}{2}\sin^{1} (u)\] sub x^2 back in \[\frac{1}{2}\sin^{1} (x^2)\]

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.2i don't see how we can do this without trig identity or trig substitution. You have to know something about those trig integral stuff to do this problem

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0doing it this way satisfies the hint of using usub ^_^

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok, so then what do i do with the limits? f(b)f(a)?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.2just plug them into the antiderivative

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yup, since, we plugged x^2 back into u you just have to plug pi/6 and pi/4 into the answer that we got up there i stopped putting them in i'm sorry, i got lazy

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.2putting them is the easy part

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0haha dont apologize, thanks for all your help, you guys saved me :)

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.2deriving them is fun too so if you don't want to memorize junk learn to derive them

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lols the smart one is to learn to derive them, that way, you can never really forget because if you forget, just derive it again :D

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hahaha i'll remember that

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.2lol right. i have to derive alot of stuff because my memory sucks

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0are you an engineering major?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0fun stuff, good luck with everything

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i'm computer engineering major

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.2computer engineering is dreamy im going to start my phd next semester and i picked to do a research in the theory of cryptography

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that sounds interesting and hard at the same time, good luck

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dreamy? what does that mean? and i like cryptography, at least i think i do...it's problem solving yes? i'm a freshman btw lols

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.2lol i think i want to date it lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lololls i love programming which involves a lot of problem solving i've only taken one programming class in college so far, and it wasn't special... i mean compared to the rest of my classes, it was awesome, but .. ehh _

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0which class? I'm a Computer Science major, love programming.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i learned matlab it's basically just a super calculator there are a lot of stuff that you can do with it but it's not really a language...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh matlab is nuts. Used a ton for scientific programming.
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