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anonymous
 5 years ago
how do i find the solution set of x squared4x12=0
anonymous
 5 years ago
how do i find the solution set of x squared4x12=0

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Use the quadratic equation.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[ax^2 + bx + c = 0 \implies x = \frac{b \pm \sqrt{b^24(a)(c)}}{2(a)}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If you haven't learned that yet, you can solve this by factoring also.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok, can you help me with the factoring part please

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oh, is it (x6)(x+2) then x6=0 add 6 to both sides = x=6 then x+2=0 sub. 2 from both sides and get x=2 so it 6 and 2? \
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