## anonymous 5 years ago how do i find the solution set of x squared-4x-12=0

1. anonymous

Use the quadratic equation.

2. anonymous

which is?...

3. anonymous

$ax^2 + bx + c = 0 \implies x = \frac{-b \pm \sqrt{b^2-4(a)(c)}}{2(a)}$

4. anonymous

If you haven't learned that yet, you can solve this by factoring also.

5. anonymous

ok, can you help me with the factoring part please

6. anonymous

Oh, is it (x-6)(x+2) then x-6=0 add 6 to both sides = x=6 then x+2=0 sub. 2 from both sides and get x=-2 so it 6 and -2? \

7. anonymous

Yes. exactly!

8. anonymous

thankyouu !!

9. anonymous

Any time =)