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anonymous

  • 5 years ago

[y^2-2y/y^2+7y-18] X [y^2-81/y^2-11y+18] Simplify the rational expression.

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  1. anonymous
    • 5 years ago
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    break the denominators off into factored squares, and cancel terms to simplify.

  2. anonymous
    • 5 years ago
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    i did that and got y(y-9)/(x-2) (y+2)

  3. anonymous
    • 5 years ago
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    polpak will help you out

  4. anonymous
    • 5 years ago
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    \[\frac{y(y - 2)}{(y+9)(y-2)} * \frac{(y+9)(y-9)}{(y+9)(y+2)} \]

  5. anonymous
    • 5 years ago
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    oh wait a sec.....on the bottom right i put (y-2) (y+2) for some reason. the rest i got right though.

  6. anonymous
    • 5 years ago
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    hold on let me try this to see if i get it right

  7. anonymous
    • 5 years ago
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    Leaves \[\frac{y(y+9)}{(y+9)(y+2)} = \frac{y(y-9)}{(y+9)(y+2)}\]

  8. anonymous
    • 5 years ago
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    Ok

  9. anonymous
    • 5 years ago
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    polpak is riqht but i think u still have to cancel the terms

  10. anonymous
    • 5 years ago
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    he did

  11. anonymous
    • 5 years ago
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    ohhh yeah he did... i didnt see the equals siqn... sorry! :))

  12. anonymous
    • 5 years ago
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    [y^2-2y/y^2+7y-18] factor you get [y(y-2)/(y-2)(y+9)]cancel you get y/(y+9) [y^2-81/y^2-11y+18] factor you get [(y+9)(y-9)]/[(y-2)(y-9)] cancel you get (y+9)/(y-2) now you can time; [y/(y+9)]*[(y+9)/(y-2)] [y^2+9y)]*[(y^2+7y-14)] from here can you do your own?

  13. anonymous
    • 5 years ago
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    would you get rid of y-2??? cuz thats the only way im getting the y(y+9)

  14. anonymous
    • 5 years ago
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    you foil

  15. anonymous
    • 5 years ago
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    time

  16. anonymous
    • 5 years ago
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    [y/(y+9)]*[(y+9)/(y-2)] sorry time not divi [y/(y+9)]*[(y+9)*(y-2)]

  17. anonymous
    • 5 years ago
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    Whoops, was that a -11 in the denominator of the second fraction?

  18. anonymous
    • 5 years ago
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    My font makes it hard to read those sometimes. Lets try this again.

  19. anonymous
    • 5 years ago
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    okay :D ha.

  20. anonymous
    • 5 years ago
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    srry I wrong again,it hard to tye ,easy for me to write

  21. anonymous
    • 5 years ago
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    \[\frac{y^2-2y}{y^2+7y-18} \times \frac{y^2-81}{y^2-11y+18}\] \[ = \frac{y(y-2)}{(y+9)(y-2)} \times \frac{(y+9)(y-9)}{(y-9)(y-2)}\] \[ = \frac{y}{(y+9)} \times \frac{(y+9)}{(y-2)}\] \[ = \frac{y(y+9)}{(y+9)(y-2)} \] \[= \frac{y}{y-2}\]

  22. anonymous
    • 5 years ago
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    [y^2+9y)]*[(y^2+7y-14)]not this [y^2+9y)]*[(y^2+7y-18)] this correct

  23. anonymous
    • 5 years ago
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    While that's correct, yours can be simplified further Nancy.

  24. anonymous
    • 5 years ago
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    Well correct assuming that by * you mean / that is.

  25. anonymous
    • 5 years ago
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    ha okay thanks polpak and nancy i really appreciate your help!

  26. anonymous
    • 5 years ago
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    Did you follow all that Carr?

  27. anonymous
    • 5 years ago
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    The best strategy to use with these is to leave them factored as long as possible so you can quickly see what cancels.

  28. anonymous
    • 5 years ago
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    yeah i got a little head of my self and put the wrong number but thank you both!

  29. anonymous
    • 5 years ago
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    That's ok, I misread a negative so we all make mistakes ;)

  30. anonymous
    • 5 years ago
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    yes still time (y/y-2)*(y+9)(y-2)*[y^2-81/y^2-11y+18]

  31. anonymous
    • 5 years ago
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    from here are you OK to do your own? [y^2+9y)]*[(y^2+7y-18)]

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