anonymous
  • anonymous
[y^2-2y/y^2+7y-18] X [y^2-81/y^2-11y+18] Simplify the rational expression.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
break the denominators off into factored squares, and cancel terms to simplify.
anonymous
  • anonymous
i did that and got y(y-9)/(x-2) (y+2)
anonymous
  • anonymous
polpak will help you out

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anonymous
  • anonymous
\[\frac{y(y - 2)}{(y+9)(y-2)} * \frac{(y+9)(y-9)}{(y+9)(y+2)} \]
anonymous
  • anonymous
oh wait a sec.....on the bottom right i put (y-2) (y+2) for some reason. the rest i got right though.
anonymous
  • anonymous
hold on let me try this to see if i get it right
anonymous
  • anonymous
Leaves \[\frac{y(y+9)}{(y+9)(y+2)} = \frac{y(y-9)}{(y+9)(y+2)}\]
anonymous
  • anonymous
Ok
anonymous
  • anonymous
polpak is riqht but i think u still have to cancel the terms
anonymous
  • anonymous
he did
anonymous
  • anonymous
ohhh yeah he did... i didnt see the equals siqn... sorry! :))
anonymous
  • anonymous
[y^2-2y/y^2+7y-18] factor you get [y(y-2)/(y-2)(y+9)]cancel you get y/(y+9) [y^2-81/y^2-11y+18] factor you get [(y+9)(y-9)]/[(y-2)(y-9)] cancel you get (y+9)/(y-2) now you can time; [y/(y+9)]*[(y+9)/(y-2)] [y^2+9y)]*[(y^2+7y-14)] from here can you do your own?
anonymous
  • anonymous
would you get rid of y-2??? cuz thats the only way im getting the y(y+9)
anonymous
  • anonymous
you foil
anonymous
  • anonymous
time
anonymous
  • anonymous
[y/(y+9)]*[(y+9)/(y-2)] sorry time not divi [y/(y+9)]*[(y+9)*(y-2)]
anonymous
  • anonymous
Whoops, was that a -11 in the denominator of the second fraction?
anonymous
  • anonymous
My font makes it hard to read those sometimes. Lets try this again.
anonymous
  • anonymous
okay :D ha.
anonymous
  • anonymous
srry I wrong again,it hard to tye ,easy for me to write
anonymous
  • anonymous
\[\frac{y^2-2y}{y^2+7y-18} \times \frac{y^2-81}{y^2-11y+18}\] \[ = \frac{y(y-2)}{(y+9)(y-2)} \times \frac{(y+9)(y-9)}{(y-9)(y-2)}\] \[ = \frac{y}{(y+9)} \times \frac{(y+9)}{(y-2)}\] \[ = \frac{y(y+9)}{(y+9)(y-2)} \] \[= \frac{y}{y-2}\]
anonymous
  • anonymous
[y^2+9y)]*[(y^2+7y-14)]not this [y^2+9y)]*[(y^2+7y-18)] this correct
anonymous
  • anonymous
While that's correct, yours can be simplified further Nancy.
anonymous
  • anonymous
Well correct assuming that by * you mean / that is.
anonymous
  • anonymous
ha okay thanks polpak and nancy i really appreciate your help!
anonymous
  • anonymous
Did you follow all that Carr?
anonymous
  • anonymous
The best strategy to use with these is to leave them factored as long as possible so you can quickly see what cancels.
anonymous
  • anonymous
yeah i got a little head of my self and put the wrong number but thank you both!
anonymous
  • anonymous
That's ok, I misread a negative so we all make mistakes ;)
anonymous
  • anonymous
yes still time (y/y-2)*(y+9)(y-2)*[y^2-81/y^2-11y+18]
anonymous
  • anonymous
from here are you OK to do your own? [y^2+9y)]*[(y^2+7y-18)]

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