Show that the equation has a root in the given interval:
3x^3-2x^2+5x+4=0 [-1,0]
The book I have explains nothing...

- anonymous

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- amistre64

We would have to factor it into is baser parts;
like 12 factors in 4 and 3

- amistre64

we can try to find a way to group it into parts that would work; but thats as much trial and error as my way :)

- amistre64

One method is to solve the equation for -1 and then for 0 and if there is a switch in signs; then it crosses the axis

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## More answers

- anonymous

who hs gmail

- anonymous

https://docs.google.com/document/d/1wPX_UwJrMAKjHc4j4mLkHwrL0rTr8ySI0m9u1KxxX2E/edit?hl=en&authkey=CMa9-_EO&pli=1#

- anonymous

go to that

- myininaya

do f(-1)
and do f(0)
if one is positive and one is negative then there is root on the interval -1..0

- amistre64

like this example

##### 1 Attachment

- anonymous

who `has gmail

- anonymous

http://uk.answers.yahoo.com/question/index?qid=20110324085500AAVlcai - This link will have the answer.

- anonymous

Okay, i'm with you

- anonymous

amistre pz go tothis link https://docs.google.com/document/d/1wPX_UwJrMAKjHc4j4mLkHwrL0rTr8ySI0m9u1KxxX2E/edit?hl=en&authkey=CMa9-_EO&pli=1#

- anonymous

Use the Intermediate Value Theorem to check for the existence of zeros (like myininaya said). If f(x) is continuous on [a, b] and if f(a) and f (b) are nonzero and have opposite signs, then f(x) has a zero in (a, b).

- anonymous

amistre plz go to this link https://docs.google.com/document/d/1wPX_UwJrMAKjHc4j4mLkHwrL0rTr8ySI0m9u1KxxX2E/edit?hl=en&authkey=CMa9-_EO&pli=1#

- amistre64

3(-1)^3-2(-1)^2+5(-1)+4 = ??
-3 -2 -5 +4 = -6
3(0)^3-2(0)^2+5(0)+4 = +4
Since -6 and 4 differ by "sign" the function has to cross the xaxis at some point in the interval between [-1,0]

- anonymous

Wow, I sure wish the book explained this stuff.

- anonymous

ammmmmmmmmmmmmmmmmmmmmmmmmmistrrrrrrrrrrrrrrrrre6444444444444444444444444444444

- amistre64

mary; please do not disrupt other peoples learning environment. If you do not have anything to contribute to the question at hand, please dont comment... thank you.

- anonymous

:)

- anonymous

but plz go to this link come on https://docs.google.com/document/d/1wPX_UwJrMAKjHc4j4mLkHwrL0rTr8ySI0m9u1KxxX2E/edit?hl=en&authkey=CMa9-_EO&pli=1#

- amistre64

email it to me, because it doesnt come out on my end....

- anonymous

whats your gmail

- amistre64

Jenn: Does that explanation make sense for you?
If you start on one side of the road and end up on the other side; youd have to have crossed the road at some point right?

- amistre64

same as it was last time :) tony031172@gmail.com

- anonymous

Yes, it makes more sense. This one is not as bad as the other one you helped me with.

- anonymous

plz check your mail now

- amistre64

lol...not as many chances to mess it up ;)

- anonymous

ok

- anonymous

Too funny..i have several more of those as well, so i'll try it

- anonymous

If I do them, will you let me know if the answer are right? Again,please..i can post them again too if you'd like

- amistre64

mary; the assassination of lincoln again? no thnx :)

- amistre64

We all can check ;)

- anonymous

Great...thank you so very much.

- amistre64

there no I in team, but there is an atem..and meat... and ate, tea eat, met, and other useful yet trivial words :)

- anonymous

i need you to help me on google doc

- anonymous

i needdd your hep

- amistre64

mary: helps is the operative word there. I am good at math, lincolns assassination, while it was a long time ago, still happened a few years before me :)

- anonymous

but plz go to gmail

- amistre64

its blank....

- anonymous

i nived you to my google doc

- anonymous

amistre why you left

- anonymous

so mean ou can help me an dget this done

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