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anonymous
 5 years ago
Show that the equation has a root in the given interval:
3x^32x^2+5x+4=0 [1,0]
The book I have explains nothing...
anonymous
 5 years ago
Show that the equation has a root in the given interval: 3x^32x^2+5x+4=0 [1,0] The book I have explains nothing...

This Question is Closed

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2We would have to factor it into is baser parts; like 12 factors in 4 and 3

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2we can try to find a way to group it into parts that would work; but thats as much trial and error as my way :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2One method is to solve the equation for 1 and then for 0 and if there is a switch in signs; then it crosses the axis

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0do f(1) and do f(0) if one is positive and one is negative then there is root on the interval 1..0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0http://uk.answers.yahoo.com/question/index?qid=20110324085500AAVlcai  This link will have the answer.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0amistre pz go tothis link https://docs.google.com/document/d/1wPX_UwJrMAKjHc4j4mLkHwrL0rTr8ySI0m9u1KxxX2E/edit?hl=en&authkey=CMa9_EO&pli=1#

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Use the Intermediate Value Theorem to check for the existence of zeros (like myininaya said). If f(x) is continuous on [a, b] and if f(a) and f (b) are nonzero and have opposite signs, then f(x) has a zero in (a, b).

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0amistre plz go to this link https://docs.google.com/document/d/1wPX_UwJrMAKjHc4j4mLkHwrL0rTr8ySI0m9u1KxxX2E/edit?hl=en&authkey=CMa9_EO&pli=1#

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.23(1)^32(1)^2+5(1)+4 = ?? 3 2 5 +4 = 6 3(0)^32(0)^2+5(0)+4 = +4 Since 6 and 4 differ by "sign" the function has to cross the xaxis at some point in the interval between [1,0]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Wow, I sure wish the book explained this stuff.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ammmmmmmmmmmmmmmmmmmmmmmmmmistrrrrrrrrrrrrrrrrre6444444444444444444444444444444

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2mary; please do not disrupt other peoples learning environment. If you do not have anything to contribute to the question at hand, please dont comment... thank you.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but plz go to this link come on https://docs.google.com/document/d/1wPX_UwJrMAKjHc4j4mLkHwrL0rTr8ySI0m9u1KxxX2E/edit?hl=en&authkey=CMa9_EO&pli=1#

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2email it to me, because it doesnt come out on my end....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2Jenn: Does that explanation make sense for you? If you start on one side of the road and end up on the other side; youd have to have crossed the road at some point right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2same as it was last time :) tony031172@gmail.com

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yes, it makes more sense. This one is not as bad as the other one you helped me with.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0plz check your mail now

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2lol...not as many chances to mess it up ;)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Too funny..i have several more of those as well, so i'll try it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If I do them, will you let me know if the answer are right? Again,please..i can post them again too if you'd like

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2mary; the assassination of lincoln again? no thnx :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Great...thank you so very much.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2there no I in team, but there is an atem..and meat... and ate, tea eat, met, and other useful yet trivial words :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i need you to help me on google doc

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2mary: helps is the operative word there. I am good at math, lincolns assassination, while it was a long time ago, still happened a few years before me :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i nived you to my google doc

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so mean ou can help me an dget this done
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