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We would have to factor it into is baser parts; like 12 factors in 4 and 3
we can try to find a way to group it into parts that would work; but thats as much trial and error as my way :)
One method is to solve the equation for -1 and then for 0 and if there is a switch in signs; then it crosses the axis
who hs gmail
go to that
do f(-1) and do f(0) if one is positive and one is negative then there is root on the interval -1..0
who `has gmail
http://uk.answers.yahoo.com/question/index?qid=20110324085500AAVlcai - This link will have the answer.
Okay, i'm with you
amistre pz go tothis link https://docs.google.com/document/d/1wPX_UwJrMAKjHc4j4mLkHwrL0rTr8ySI0m9u1KxxX2E/edit?hl=en&authkey=CMa9-_EO&pli=1#
Use the Intermediate Value Theorem to check for the existence of zeros (like myininaya said). If f(x) is continuous on [a, b] and if f(a) and f (b) are nonzero and have opposite signs, then f(x) has a zero in (a, b).
amistre plz go to this link https://docs.google.com/document/d/1wPX_UwJrMAKjHc4j4mLkHwrL0rTr8ySI0m9u1KxxX2E/edit?hl=en&authkey=CMa9-_EO&pli=1#
3(-1)^3-2(-1)^2+5(-1)+4 = ?? -3 -2 -5 +4 = -6 3(0)^3-2(0)^2+5(0)+4 = +4 Since -6 and 4 differ by "sign" the function has to cross the xaxis at some point in the interval between [-1,0]
Wow, I sure wish the book explained this stuff.
mary; please do not disrupt other peoples learning environment. If you do not have anything to contribute to the question at hand, please dont comment... thank you.
but plz go to this link come on https://docs.google.com/document/d/1wPX_UwJrMAKjHc4j4mLkHwrL0rTr8ySI0m9u1KxxX2E/edit?hl=en&authkey=CMa9-_EO&pli=1#
email it to me, because it doesnt come out on my end....
whats your gmail
Jenn: Does that explanation make sense for you? If you start on one side of the road and end up on the other side; youd have to have crossed the road at some point right?
Yes, it makes more sense. This one is not as bad as the other one you helped me with.
plz check your mail now
lol...not as many chances to mess it up ;)
Too funny..i have several more of those as well, so i'll try it
If I do them, will you let me know if the answer are right? Again,please..i can post them again too if you'd like
mary; the assassination of lincoln again? no thnx :)
We all can check ;)
Great...thank you so very much.
there no I in team, but there is an atem..and meat... and ate, tea eat, met, and other useful yet trivial words :)
i need you to help me on google doc
i needdd your hep
mary: helps is the operative word there. I am good at math, lincolns assassination, while it was a long time ago, still happened a few years before me :)
but plz go to gmail
i nived you to my google doc
amistre why you left
so mean ou can help me an dget this done