anonymous
  • anonymous
Show that the equation has a root in the given interval: 3x^3-2x^2+5x+4=0 [-1,0] The book I have explains nothing...
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
amistre64
  • amistre64
We would have to factor it into is baser parts; like 12 factors in 4 and 3
amistre64
  • amistre64
we can try to find a way to group it into parts that would work; but thats as much trial and error as my way :)
amistre64
  • amistre64
One method is to solve the equation for -1 and then for 0 and if there is a switch in signs; then it crosses the axis

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anonymous
  • anonymous
who hs gmail
anonymous
  • anonymous
https://docs.google.com/document/d/1wPX_UwJrMAKjHc4j4mLkHwrL0rTr8ySI0m9u1KxxX2E/edit?hl=en&authkey=CMa9-_EO&pli=1#
anonymous
  • anonymous
go to that
myininaya
  • myininaya
do f(-1) and do f(0) if one is positive and one is negative then there is root on the interval -1..0
amistre64
  • amistre64
like this example
1 Attachment
anonymous
  • anonymous
who `has gmail
anonymous
  • anonymous
http://uk.answers.yahoo.com/question/index?qid=20110324085500AAVlcai - This link will have the answer.
anonymous
  • anonymous
Okay, i'm with you
anonymous
  • anonymous
amistre pz go tothis link https://docs.google.com/document/d/1wPX_UwJrMAKjHc4j4mLkHwrL0rTr8ySI0m9u1KxxX2E/edit?hl=en&authkey=CMa9-_EO&pli=1#
anonymous
  • anonymous
Use the Intermediate Value Theorem to check for the existence of zeros (like myininaya said). If f(x) is continuous on [a, b] and if f(a) and f (b) are nonzero and have opposite signs, then f(x) has a zero in (a, b).
anonymous
  • anonymous
amistre plz go to this link https://docs.google.com/document/d/1wPX_UwJrMAKjHc4j4mLkHwrL0rTr8ySI0m9u1KxxX2E/edit?hl=en&authkey=CMa9-_EO&pli=1#
amistre64
  • amistre64
3(-1)^3-2(-1)^2+5(-1)+4 = ?? -3 -2 -5 +4 = -6 3(0)^3-2(0)^2+5(0)+4 = +4 Since -6 and 4 differ by "sign" the function has to cross the xaxis at some point in the interval between [-1,0]
anonymous
  • anonymous
Wow, I sure wish the book explained this stuff.
anonymous
  • anonymous
ammmmmmmmmmmmmmmmmmmmmmmmmmistrrrrrrrrrrrrrrrrre6444444444444444444444444444444
amistre64
  • amistre64
mary; please do not disrupt other peoples learning environment. If you do not have anything to contribute to the question at hand, please dont comment... thank you.
anonymous
  • anonymous
:)
anonymous
  • anonymous
but plz go to this link come on https://docs.google.com/document/d/1wPX_UwJrMAKjHc4j4mLkHwrL0rTr8ySI0m9u1KxxX2E/edit?hl=en&authkey=CMa9-_EO&pli=1#
amistre64
  • amistre64
email it to me, because it doesnt come out on my end....
anonymous
  • anonymous
whats your gmail
amistre64
  • amistre64
Jenn: Does that explanation make sense for you? If you start on one side of the road and end up on the other side; youd have to have crossed the road at some point right?
amistre64
  • amistre64
same as it was last time :) tony031172@gmail.com
anonymous
  • anonymous
Yes, it makes more sense. This one is not as bad as the other one you helped me with.
anonymous
  • anonymous
plz check your mail now
amistre64
  • amistre64
lol...not as many chances to mess it up ;)
anonymous
  • anonymous
ok
anonymous
  • anonymous
Too funny..i have several more of those as well, so i'll try it
anonymous
  • anonymous
If I do them, will you let me know if the answer are right? Again,please..i can post them again too if you'd like
amistre64
  • amistre64
mary; the assassination of lincoln again? no thnx :)
amistre64
  • amistre64
We all can check ;)
anonymous
  • anonymous
Great...thank you so very much.
amistre64
  • amistre64
there no I in team, but there is an atem..and meat... and ate, tea eat, met, and other useful yet trivial words :)
anonymous
  • anonymous
i need you to help me on google doc
anonymous
  • anonymous
i needdd your hep
amistre64
  • amistre64
mary: helps is the operative word there. I am good at math, lincolns assassination, while it was a long time ago, still happened a few years before me :)
anonymous
  • anonymous
but plz go to gmail
amistre64
  • amistre64
its blank....
anonymous
  • anonymous
i nived you to my google doc
anonymous
  • anonymous
amistre why you left
anonymous
  • anonymous
so mean ou can help me an dget this done

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