What is the area of the trapezoid given X=13 , y=9 and A = 55 degree? A.)164.5cm^2 B.)210.3cm^3 C.)133.9cm^2 D.)267.8cm^2 *sn the picture is there when you click on the picture. Please help thanks

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

What is the area of the trapezoid given X=13 , y=9 and A = 55 degree? A.)164.5cm^2 B.)210.3cm^3 C.)133.9cm^2 D.)267.8cm^2 *sn the picture is there when you click on the picture. Please help thanks

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

1 Attachment
Height of the trapezoid can be found be taking the sin 55 Sin is opposite/hypothenuse Sin 55 = h/19 Sin 55 = h 7.37 = h You also need to know the two bases.. The one base is x which is 13. The other base is 13 + whatever 2 of those extra lengths are. The extra lengths are the cos 55.. cos 55 = L/9 9 cos 55 = L 5.16 = L So the other base is 5.16 + 13 + 5.16 = 23.32 The formula for area of a trapezoid is 1/2h(b1 + b2) A = 1/2 * 7.37(13 + 23.32) A = 133.9 cm^2
so its c

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Not the answer you are looking for?

Search for more explanations.

Ask your own question