anonymous
  • anonymous
another one
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
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anonymous
  • anonymous
that last page was making my browser laggy
anonymous
  • anonymous
sorry:S

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anonymous
  • anonymous
soo?:)
anonymous
  • anonymous
trying to figure out a clever way to do it so I don't have to do all that multiplication
anonymous
  • anonymous
well I know that A^2n = I and A^2n+1 = A from my matrix calculator
anonymous
  • anonymous
so the solution and the steps is A^2n = I and A^2n+1 = A only??
anonymous
  • anonymous
yeah, but you are going to need to show how you got that
anonymous
  • anonymous
yeah actually:S:S sorry
anonymous
  • anonymous
okay: for the muliplication on the diagonal we get: (1/2)^2 + (-1/2)^2 + (-1/2)^2 + (-1/2)^2 = 1
anonymous
  • anonymous
for not on the diagonal we get: 1/2*-1/2 + 1/2*-1/2 + 1/2*1/2 + 1/2*1/2 = 0
anonymous
  • anonymous
see I did part a but the problem in part B
anonymous
  • anonymous
So A^2 = identity matrix then A^3 = A^2 * A = Identity * A = A
anonymous
  • anonymous
well then for A^2m it's just (A^2)^n which is just multiplying an Identity matrix a bunch of times
anonymous
  • anonymous
for A^2n+1 = A^2n * A = (A^2)^n * A = A
anonymous
  • anonymous
thats all?
anonymous
  • anonymous
yep A^2n = (A^2)^n = Id^n = Id A^2n+1 = (A^2)^n * A= Id * A = A
anonymous
  • anonymous
thanks:)
anonymous
  • anonymous
find conditions on a and b such that the following system of linear equations has a no solution b unique solution or c infinitely solution x+y+3z=2 x+2y+4z=3 x+3y+az=b
anonymous
  • anonymous
hmm
anonymous
  • anonymous
sorry Iam making u tired :)
anonymous
  • anonymous
not sure how to effectively do that one.

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