Will someone please help me with four problems?

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Will someone please help me with four problems?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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finding the surface area of these two regular pyramids
picture 124, 270.00cm is erea base? picture 125, 296.05cm is erea base?
no those where what i got when i did them and they are wrong

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I want double check 124 the base is square?
picture 125 the base 5 side ?
124 base is a triangle. 125 base is 6 sides
ok, I m not good eyes. I will working this
h is the high triangle; c is the high of the base of triangle h= √((12)^2-3^2 ) = 11.6 Area triangle= (6*11.6)/2 = 34.8 cm^2 Area for 6 triangles: 34.8*6= 208.8 cm^2 (360°)/6=60 , 60/2 = 30° cos30 = c/12 c = 12cos30 =10.4cm Area base = (base*high*side)/2 (6*10.4*6)/2 = 187.2cm^2 Area base + Area Triangle : 187.2 ^2 +208.8cm^2 = 396cm^2 You check caculator made sure I'm caculater right
124 I can see which one base, which one high

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