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anonymous

  • 5 years ago

Will someone please help me with four problems?

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  1. anonymous
    • 5 years ago
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    finding the surface area of these two regular pyramids

  2. anonymous
    • 5 years ago
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    picture 124, 270.00cm is erea base? picture 125, 296.05cm is erea base?

  3. anonymous
    • 5 years ago
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    no those where what i got when i did them and they are wrong

  4. anonymous
    • 5 years ago
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    I want double check 124 the base is square?

  5. anonymous
    • 5 years ago
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    picture 125 the base 5 side ?

  6. anonymous
    • 5 years ago
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    124 base is a triangle. 125 base is 6 sides

  7. anonymous
    • 5 years ago
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    ok, I m not good eyes. I will working this

  8. anonymous
    • 5 years ago
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    h is the high triangle; c is the high of the base of triangle h= √((12)^2-3^2 ) = 11.6 Area triangle= (6*11.6)/2 = 34.8 cm^2 Area for 6 triangles: 34.8*6= 208.8 cm^2 (360°)/6=60 , 60/2 = 30° cos30 = c/12 c = 12cos30 =10.4cm Area base = (base*high*side)/2 (6*10.4*6)/2 = 187.2cm^2 Area base + Area Triangle : 187.2 ^2 +208.8cm^2 = 396cm^2 You check caculator made sure I'm caculater right

  9. anonymous
    • 5 years ago
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    124 I can see which one base, which one high

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spraguer (Moderator)
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