anonymous
  • anonymous
Please help Evaluate the polynomial function for the given values of the variable P(s)=2sᶟ-9s-10 P(1/2) and P(0)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
p(1/2)= 2 * (1/2)^3 - 9*(1/2) - 10
anonymous
  • anonymous
P(1/2) = P(s) with s = 1/2
anonymous
  • anonymous
P(1/2) = -57/4 P(0) = -10

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anonymous
  • anonymous
so set s = 1/2 and 0 in your equation and evaluate it.
anonymous
  • anonymous
http://m.wolframalpha.com/input/?i=2x^3-9x-10%2C+x%3D1%2F2&x=0&y=0
anonymous
  • anonymous
thank you but i would like to work the problem myself step by step so i can do it on my own
anonymous
  • anonymous
Then just plug in the values 1/2 and 0 to the functions.
anonymous
  • anonymous
Ok.... do it by your self, and then check the answers using wolfram
anonymous
  • anonymous
i dont know how i havent done this kind of math in along time will u explain it step by step
anonymous
  • anonymous
So are you having problems multiplying, adding and subtracting with a fraction?
anonymous
  • anonymous
yes i am i hate fractions never been good at them
anonymous
  • anonymous
okay. lets take this one step at a time P(s)=2sᶟ-9s-10 s = 1/2 P(1/2) = 2 * (1/2)^3 - 9(1/2) -10
anonymous
  • anonymous
(1/2)^3 = 1/2*1/2*1/2 = 1/8 2(1/2)^3 = 2*1/8 = 1/4 9(1/2) = 9/2 so, P(1/2) = 1/4-9/2-10
anonymous
  • anonymous
9/2 is nothing but 18/4 and 10 is nothing but 40/4 so, P(1/2) = 1/4 - 18/4 - 40/4 = (1-18-40)/4 = -57/4
anonymous
  • anonymous
2(1/2)^3= how did u get 2*1/8
anonymous
  • anonymous
what \[(1/2)^3\] its (1/2) *(1/2) *(1/2)= 1/8 but dont forget 2 2/8 = 1/4

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