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anonymous
 5 years ago
Show that the equation has a root in the given interval.
x^4+3x^2+5=0 [2,3]
anonymous
 5 years ago
Show that the equation has a root in the given interval. x^4+3x^2+5=0 [2,3]

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Plug in 2, and then 3. The sign of the function will change. That means it's cut the xaxis at least once, and so there is at least one real root in that interval.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0f(2) = 1 f(3) = 49 Look at the graph between x=1 and x=3, you'll see it shoots straight down.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Am I plugging it as this: f(2) = (2)^4 + 3(2)^2 +5

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No. \[f(2)=(2)^4+3(2)^2+5=16+12+5=1\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You replace x with 2, not 2.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Same for 3:\[f(3)=(3)^4+3(3)^2+5=81+27+5=49\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I have to log off. Just be careful when you sub. numbers in for x...
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