anonymous
  • anonymous
The tangent line to the graph y=e^(2-x) at the point (1,e) intersects both coordinate axes. What is the areas of the triangle formed by this tangent line and the coordinate axes?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Take the derivative of the function.. you will get -e^(2-x) Put one in the 1, you will get -e. This is the slope of your tangent Now find the x and y intercepts, and use the 1/2 (xint) * (yint) You will get area.
anonymous
  • anonymous
the answer should be 2e
anonymous
  • anonymous
So I find the x-int and y-int using the derivative.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
you set up the equation as y = -ex + b and first you plug in 1 as x and e as y, to get b, which is your y intercept, and then you use the new equation -ex+2e =y and set y to 0, which well give x = 2, your x int
anonymous
  • anonymous
Okay thank you!
anonymous
  • anonymous
np medal me

Looking for something else?

Not the answer you are looking for? Search for more explanations.