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anonymous
 5 years ago
equation of a line perpendicular to y=3x1?
anonymous
 5 years ago
equation of a line perpendicular to y=3x1?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0perpendicular line is the negative reciprocal so the slope of the line has to be \[\frac{1}{3}\] since there's no point, you can put any constant or you can just leave it at zero \[y = \frac{1}{3}x\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what do you mean since there's no point? what about the 1?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.2hes says your question did't say what point the perpendicular line was running through

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the 1 is the intercept for y = 3x 1 but the question asks you for equation of A line, so ANY line it can be y = (1/3)x or y = (1/3)x + 3 y = (1/3)x + 5 it can be any number because the question doesn't specify a specific point that the line has to go through

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it says it has to pass through the point of intersection from these two equations: y=24/x and y=3x1

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.2y=(1/3)x+C where C is a constant is the general perpendicular line for the line y=3x+K where K can be any constant

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it has to pass through the point where those two equations intersect?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so set those equations equal to one another and solve for the point 24/x = 3x  1 3x^2 x = 24 3x^2  x  24 = 0 x = (8/3), 3 myininaya, what am i doing wrong? how can i get two intersections for two lines???

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.224/x is not a line its a hyperbola

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh wait yeah, i didn't catch that..

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.2so since we have two intersections and your question didn't specify which intersection we have 2 equations: they both have the the form y=(1/3)x+C so we have 1 equation with x=8/3 so y=3(8/3)1=9 so we have 9=(1/3)(8/3)+b solve for b to find the y intercept and we also have equation 2 with x=3 so y=3(3)1=8 so we have 8=(1/3)(3)+b solve this for b and you have your two equations

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.2so the first equation we have 98/9=b so b=89/9 so equation 1 is y=(1/3)x89/9 and the second equation we have 8+1=b so b=9 so equation 2 is y=(1/3)x+9

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.2your welcome. what class is that? is that really algebra? That is hard question for algebra students. no offense. i would know since I teach algebra

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.2i like it though. I might give it as a project hehe

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0International Baccalaureate its a higher level of math offered worldwide

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.2i wish i was challenged more but I guess I know enough lol, but no one could really know enough so I take that back

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its like college level math. well all of my courses are ib.

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.2so did you understand everything above?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this is supposed to be an easy problem compared to the other problems we learn lol yes i did thank you !

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.2i really liked your problem. its nice
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