anonymous
  • anonymous
equation of a line perpendicular to y=3x-1?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
perpendicular line is the negative reciprocal so the slope of the line has to be \[-\frac{1}{3}\] since there's no point, you can put any constant or you can just leave it at zero \[y = -\frac{1}{3}x\]
anonymous
  • anonymous
what do you mean since there's no point? what about the -1?
myininaya
  • myininaya
hes says your question did't say what point the perpendicular line was running through

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anonymous
  • anonymous
the -1 is the intercept for y = 3x -1 but the question asks you for equation of A line, so ANY line it can be y = -(1/3)x or y = -(1/3)x + 3 y = -(1/3)x + 5 it can be any number because the question doesn't specify a specific point that the line has to go through
anonymous
  • anonymous
it says it has to pass through the point of intersection from these two equations: y=24/x and y=3x-1
myininaya
  • myininaya
y=-(1/3)x+C where C is a constant is the general perpendicular line for the line y=3x+K where K can be any constant
anonymous
  • anonymous
it has to pass through the point where those two equations intersect?
anonymous
  • anonymous
yes
myininaya
  • myininaya
set 24/x=3x-1
myininaya
  • myininaya
solve for x
anonymous
  • anonymous
so set those equations equal to one another and solve for the point 24/x = 3x - 1 3x^2 -x = 24 3x^2 - x - 24 = 0 x = -(8/3), 3 myininaya, what am i doing wrong? how can i get two intersections for two lines???
myininaya
  • myininaya
24/x is not a line its a hyperbola
anonymous
  • anonymous
oh wait yeah, i didn't catch that..
myininaya
  • myininaya
so since we have two intersections and your question didn't specify which intersection we have 2 equations: they both have the the form y=-(1/3)x+C so we have 1 equation with x=-8/3 so y=3(-8/3)-1=-9 so we have -9=-(1/3)(-8/3)+b solve for b to find the y intercept and we also have equation 2 with x=3 so y=3(3)-1=8 so we have 8=-(1/3)(3)+b solve this for b and you have your two equations
myininaya
  • myininaya
so the first equation we have -9-8/9=b so b=-89/9 so equation 1 is y=-(1/3)x-89/9 and the second equation we have 8+1=b so b=9 so equation 2 is y=-(1/3)x+9
anonymous
  • anonymous
thank you !
myininaya
  • myininaya
your welcome. what class is that? is that really algebra? That is hard question for algebra students. no offense. i would know since I teach algebra
myininaya
  • myininaya
i like it though. I might give it as a project hehe
anonymous
  • anonymous
ib math studies :)
myininaya
  • myininaya
ib?
anonymous
  • anonymous
International Baccalaureate its a higher level of math offered worldwide
myininaya
  • myininaya
i am jealous
myininaya
  • myininaya
i wish i was challenged more but I guess I know enough lol, but no one could really know enough so I take that back
anonymous
  • anonymous
its like college level math. well all of my courses are ib.
myininaya
  • myininaya
so did you understand everything above?
anonymous
  • anonymous
this is supposed to be an easy problem compared to the other problems we learn lol yes i did thank you !
myininaya
  • myininaya
i really liked your problem. its nice

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