anonymous
  • anonymous
I need help on quadratic equations its so difficult the problem is (x+4) (x-9)=4x can someone please help me
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
You need to expand the left-hand side and collect like terms. You will end up with another quadratic which you can factor and solve.
anonymous
  • anonymous
\[(x+4)(x-9)=4x \iff x^2+4x-9x-36=4x \iff x^2-9x-36=0\]which may be factored\[(x+3)(x-12)=0\]
anonymous
  • anonymous
x^2-9 x-36 = 0

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anonymous
  • anonymous
Your solutions are then \[x=-3, x=12\]
anonymous
  • anonymous
(x-12)(x+3)
anonymous
  • anonymous
Foil the (x+4)(x-9) which comes out as x^2-5x-36=4x then you subtract 4x on both sides which leaves you with x^2-9x-36=0 then factor it to (x-12)(x+3)=0 x=12 x=-3
anonymous
  • anonymous
Thank you all very much
anonymous
  • anonymous
welcome
anonymous
  • anonymous
Can someone explain to me how to do quadratic equations, im confused?
anonymous
  • anonymous
Look under 'algebra' on this site. In the second column, there should be stuff for the quadratic equation. http://www.khanacademy.org/

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