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anonymous

  • 5 years ago

solve 16(^x+2) = 8(^-x)

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  1. anonymous
    • 5 years ago
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    Is this \[16^{x +2}\]?

  2. anonymous
    • 5 years ago
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    Yes, yes it is

  3. anonymous
    • 5 years ago
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    If you notice 16 and 8 are factors of 2 you can convert 16 as a power of 2. For example if one of the numbers were 4 you can make it

  4. anonymous
    • 5 years ago
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    \[2^{2}\]

  5. anonymous
    • 5 years ago
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    Oh so 2^4 will get me 16 and then 2^3 will get me 8 correct?

  6. anonymous
    • 5 years ago
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    Or can i even do it by 8 and have 8^2 and 8

  7. anonymous
    • 5 years ago
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    No, that way won't get you there 8 squared is 64

  8. anonymous
    • 5 years ago
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    oh your right :* silly me haha but i dont get how to get to what x= like how to get X by itself

  9. anonymous
    • 5 years ago
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    Once you have them on even footing 2 square something: Your new exponents would be 4(x+2)=3(-x) This is your new equation. Solve for x.

  10. anonymous
    • 5 years ago
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    Oh ok now all i do is distribute the 4 and 3 so 4x+8=-3x then +3x and stuff and get 7x=-8 is the answer which is x= -7/8 :] right!

  11. anonymous
    • 5 years ago
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    -8/7 =x actually

  12. anonymous
    • 5 years ago
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    Right. That's the method. I haven't checked whether you're right or wrong. You can do that.

  13. anonymous
    • 5 years ago
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    Thank you very much

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