anonymous
  • anonymous
solve 16(^x+2) = 8(^-x)
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
Is this \[16^{x +2}\]?
anonymous
  • anonymous
Yes, yes it is
anonymous
  • anonymous
If you notice 16 and 8 are factors of 2 you can convert 16 as a power of 2. For example if one of the numbers were 4 you can make it

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anonymous
  • anonymous
\[2^{2}\]
anonymous
  • anonymous
Oh so 2^4 will get me 16 and then 2^3 will get me 8 correct?
anonymous
  • anonymous
Or can i even do it by 8 and have 8^2 and 8
anonymous
  • anonymous
No, that way won't get you there 8 squared is 64
anonymous
  • anonymous
oh your right :* silly me haha but i dont get how to get to what x= like how to get X by itself
anonymous
  • anonymous
Once you have them on even footing 2 square something: Your new exponents would be 4(x+2)=3(-x) This is your new equation. Solve for x.
anonymous
  • anonymous
Oh ok now all i do is distribute the 4 and 3 so 4x+8=-3x then +3x and stuff and get 7x=-8 is the answer which is x= -7/8 :] right!
anonymous
  • anonymous
-8/7 =x actually
anonymous
  • anonymous
Right. That's the method. I haven't checked whether you're right or wrong. You can do that.
anonymous
  • anonymous
Thank you very much

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