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anonymous
 5 years ago
solve 16(^x+2) = 8(^x)
anonymous
 5 years ago
solve 16(^x+2) = 8(^x)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Is this \[16^{x +2}\]?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If you notice 16 and 8 are factors of 2 you can convert 16 as a power of 2. For example if one of the numbers were 4 you can make it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oh so 2^4 will get me 16 and then 2^3 will get me 8 correct?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Or can i even do it by 8 and have 8^2 and 8

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No, that way won't get you there 8 squared is 64

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh your right :* silly me haha but i dont get how to get to what x= like how to get X by itself

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Once you have them on even footing 2 square something: Your new exponents would be 4(x+2)=3(x) This is your new equation. Solve for x.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oh ok now all i do is distribute the 4 and 3 so 4x+8=3x then +3x and stuff and get 7x=8 is the answer which is x= 7/8 :] right!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Right. That's the method. I haven't checked whether you're right or wrong. You can do that.
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