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- anonymous

solve 16(^x+2) = 8(^-x)

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- anonymous

solve 16(^x+2) = 8(^-x)

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- anonymous

Is this \[16^{x +2}\]?

- anonymous

Yes, yes it is

- anonymous

If you notice 16 and 8 are factors of 2 you can convert 16 as a power of 2. For example if one of the numbers were 4 you can make it

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- anonymous

\[2^{2}\]

- anonymous

Oh so 2^4 will get me 16 and then 2^3 will get me 8 correct?

- anonymous

Or can i even do it by 8 and have 8^2 and 8

- anonymous

No, that way won't get you there 8 squared is 64

- anonymous

oh your right :* silly me haha but i dont get how to get to what x= like how to get X by itself

- anonymous

Once you have them on even footing 2 square something: Your new exponents would be 4(x+2)=3(-x) This is your new equation. Solve for x.

- anonymous

Oh ok now all i do is distribute the 4 and 3 so 4x+8=-3x then +3x and stuff and get 7x=-8 is the answer which is x= -7/8 :] right!

- anonymous

-8/7 =x actually

- anonymous

Right. That's the method. I haven't checked whether you're right or wrong. You can do that.

- anonymous

Thank you very much

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