## anonymous 5 years ago what is the integral of 1/lnt dt

I believe it is $(t-1)/ln(t)$ however I am not a hundred percent sure. $I = \int\limits(1/\ln(t))dt = t/\ln(t) + \int\limits(1/\ln^2(t))dt = t/\ln(t) - 1/\ln(t) = (t-1)/\ln(t)$