anonymous
  • anonymous
solve for x: x^2 + 5x is > or = 6
Mathematics
katieb
  • katieb
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myininaya
  • myininaya
x^2+5x-6>=0 (x+6)(x-1)>=0 when is this LHS zero?
myininaya
  • myininaya
when x=___ and x=___?
anonymous
  • anonymous
What is LHS..?

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anonymous
  • anonymous
You would use the (x + 6)(x - 1) >= 0 When x <=-6 or x >= 1
anonymous
  • anonymous
from the (X+6) you would then solve for x for both giving you the positive 1 and negative 6 correct?
anonymous
  • anonymous
That would give you when it = 0, but when would it be > 0... see my earlier response
anonymous
  • anonymous
Then where are you getting the positive and negative...... your doing x+6=0 or x-1+0 ... right
myininaya
  • myininaya
(-inf,-6]u[1,inf)
anonymous
  • anonymous
What.... does that say

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