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- anonymous

Solve the equation.
square root of 5x+1=6
square root of x-2 +7=-4
x2+7x+4=0
5x2=-15

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- anonymous

Solve the equation.
square root of 5x+1=6
square root of x-2 +7=-4
x2+7x+4=0
5x2=-15

- chestercat

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- anonymous

1) x=7
2) x=123
3) x=-6.37, -.63
4) x=9

- anonymous

how did u get these answers

- radar

Would like to see how the answer to the 4th one was developed. when 9 is substitued in the equation:
\[5(9)^{2}=-15\]
\[(9)^{2}=-15/5=-3\]
\[81\neq-3\]

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- anonymous

Yeah, my bad I read it wrong. It's actually 3i.

- radar

Gettin there...... how about \[i \sqrt{3}\]

- anonymous

\[5x ^{2}= -15\]
\[X ^{2}= -15\div5=-3\]
\[X=\sqrt{-3}\]
\[X= i \sqrt{3}\]

- anonymous

Sorry about that, I'm new to this and I hadn't yet figured out the equation inserts.

- radar

What method did you use on number 3. Did you use quadratic formula?

- anonymous

Yes. First I put it in the equation and solved, simplifying tona decimal and rounding to the nearest hundredth.
I also checked the zeroes on the graph.

- anonymous

5x^2 = -15
x^2 = -3 take the square root
x = +- i sqrt(3)

- radar

Very good. lerachia is there any more questions?

- radar

blexting thanks , so their is two answers for number 4
\[i \sqrt{3}\]\[-i \sqrt{3}\]

- radar

lerachia, do you understand how quantum torch got those answers or do you care?

- anonymous

Yes, when you move an even power (either the numerator or denominator) there are multiple answers. I don't know how to write that with the equation thing yet though, but the rule applies, so thanks on my part as well.

- radar

good night all.

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