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x=5/2 and x=3? just plot them?

x=5/2 and x=-3.

Yes, take a number line and plot those points. You'll see that it's partitioned into three regions.

Now pick a point in the first region that's easy to do the math with. So, maybe pick x=-5.

And test in the original inequality.

right. i ended up shading the region between the two points becasue it includes all of them?

No...don't shade...it's just a visual to assist.

So the solution is\[\left\{ x|-3 \lt x \lt \frac{5}{2} \right\}\]

so how do i check the points? could you show how?

You just plug them in to the inequality to see if it gives you something that's true or not.

ok so pluggin in 0 it would be -4=0 which is not true?

Here, for x=0,\[0(4-x)=0>0\]That's NOT true - a number CANNOT be bigger than itself.

So 0 is NOT included.

so use a number beyond four? like 8? so 32=0 which is not true?

Yep, choose a number beyond for to test for the interval,
4

*four

Go back to the inequality..! Not the equality.

so id end up with 04

\[8(4-8)=-32\]which is NOT greater than 0, so all x's above x=4 are NOT included.

awesome helped a lot thanks

You should have\[(-\infty, 0) \cup (4, \infty)\]as your interval.

It means everything on the number line, except for everything in between and including, 0 and 4.

One thing: your notation above
04
shouldn't be used. In mathematics, you just write
x<0 or x>4

The notation 04 has no meaning...which might get you in trouble when it comes to assessment.