anonymous
  • anonymous
while on vacation Kevin went for a swim. Swimming against the current took 8 min. to go 200 meters coming back took half as long. Find Kevin's average swimming speed and the water current.
Mathematics
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anonymous
  • anonymous
while on vacation Kevin went for a swim. Swimming against the current took 8 min. to go 200 meters coming back took half as long. Find Kevin's average swimming speed and the water current.
Mathematics
chestercat
  • chestercat
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
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radar
  • radar
Let x = current speed in meters/sec Let y = Kevin's speed in same units then we can use the s=rt formula where s=distance, r = speed, and t = time Then kevins speed swimming against current is y-x kevins speed swimming with the current is y+x
radar
  • radar
The distance was the same both ways 200 meters. Here are two equations for each trip 200 = 8(y-x) (8 minutes when swimming against current ) eq1 200 = 4(y+x) (4 minutes half the time when swimming with the current) eq2 200=8y-8x eq 1 200=4y+4x eq 2 400=8y+8x eq 2 multiplied by 2 200=8y-8x eq 1 600=16y adding y=37.5 meters/min substituting in eq 2 200=4(37.5) + 4x becomes 200=150+4x becomes 4x=50 or x =12.5 meter/min Change the units in my first post to meters/min as minutes were the units given in the problem.

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