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anonymous

  • 5 years ago

while on vacation Kevin went for a swim. Swimming against the current took 8 min. to go 200 meters coming back took half as long. Find Kevin's average swimming speed and the water current.

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  1. anonymous
    • 5 years ago
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    Will give medal 4 the help.

  2. anonymous
    • 5 years ago
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    d= rt 200m = 8 min ( Kevin- Current) Kevin - current = 25m/min 200m = 4 min (Kevin + current) Kevin + current = 50 Now you add subtract Kevin - current from Kevin + current to get... Kevin + current - (Kevin - current) = 50m/min - 25m/min 2 current = 25m/min current = 12.5m/min Now we plug current in and solve Kevin + 12.5m/min = 50 Kevin = 37.5m/min Hope that helps

  3. anonymous
    • 5 years ago
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    thanks

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