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anonymous
 5 years ago
The rate at which water is sprayed on a field of vegetables is given by R(t)=2sqrt(1+5t^3), where t is in minutes and R(t) is in gallons per minute. During the time interval 0 to 4 inclusive, what is the average rate of water flow, in gallons per minute?
anonymous
 5 years ago
The rate at which water is sprayed on a field of vegetables is given by R(t)=2sqrt(1+5t^3), where t is in minutes and R(t) is in gallons per minute. During the time interval 0 to 4 inclusive, what is the average rate of water flow, in gallons per minute?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The formula is 1/ba int(equation) from zero to four. Just integrate normally and multiply by the first part.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0integrate with limits 0,4 then divide by 4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ie, \[1\div4 \int\limits_{0}^{4} 2\sqrt{1+5t ^{3}} dt\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I got 14.691 What do a & b represent in the average rate equation?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It is the average value theorem.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Essentially, to explain geometrically, it is the same as taking the average of any numbers. You take the sum and then divide by how many numbers you had originally, right? You had a certain amount between b, which is 4, and a, which is 2. That is represented by the integration. You divide by their difference because it is the space between in terms of x, or in this case, t. Does that answer your question?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Therefore, the average value theorem states that the average value is simply the integration times 1/ba

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm sorry, that was a typo. A is 0.
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