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anonymous
 5 years ago
f(x)=x^2x4
Determine
a. if f has a maximum value or a minimum
b. the value of x at which the max or min occurs
c. the max or min value of f
anonymous
 5 years ago
f(x)=x^2x4 Determine a. if f has a maximum value or a minimum b. the value of x at which the max or min occurs c. the max or min value of f

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myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0the parabola is oven downward so we have an upside down U that means we have a max

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0a. maximum b. x = 1/2 c. 9/2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0A) derive, set equal to zero. There will be two. Test both critical points. If it goes from positive to negative, it's a max. If it's opposite, it's a min. If there is no change, which there won't be in this instance, it tells you nothing. B) the values you tested in a. C) plug the values in from b and solve for y.

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0f(x)=(x^2+x)4=(x^2+x+(1/2)^2)4+(1/2)^2 =(x+1/2)^24+1/4=(x+1/2)^215/4 so the vertex=(1/2,15/4)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Correction, theres one critical point.
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