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anonymous
 5 years ago
need to find the solution to this equation.
anonymous
 5 years ago
need to find the solution to this equation.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[y ^{1}22y _{2}^{1}+12=0\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I couldn't get this to look right. it is supposed to be y with the 1/2 as the square root

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Is it \[{1 \over y}22y^{1/2}+12=0?\]

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1let u=y^(1/2) so we have u^2=y^(1)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I got 12 and 10. is that correct?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0or maybe they are negative?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1one sec im scanning something

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wow, thanks for doing that! I can see where I maybe slipped up. I am a bit confused as to what the answer is though. Is there still one more step in solving those 2 solutions?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0for some reason i'm not getting a whole number

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1i'm not getting a whole number

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i just realized that you had 12 in the problem when it's supposed to be 120. Sorry if I typed it wrong.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yep, I did... ahh. sorry.

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1lol. okay lets take another look at it

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1so we get u=10 and u=12 like you been talking about this whole time but u=y^(1/2) y^(1/2)=10 and y^(1/2)=12 so y=10^(2)=1/(10^2)=1/100 so y=12^(2)=1/(12^2)=1/144 there you basically had it you just needed to solve for y

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1we got u=12 and 10 because u^222u+120=(u12)*(u10)=0 so very good

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok I just wasn't sure if they were supposed to stay positive.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Thanks for clarifying!

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1to get rid of that 1/2 exponent i just raised both sides to 2 because law of exponents tells me if we have (x^{1/2)^{2} to multiply the exponents but if i do this to one side i have to do it to the other
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