O.k. this is a easy one,however,I've forgotten the process.Pls.refresh my memory on this equation: y-2+3y=10

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O.k. this is a easy one,however,I've forgotten the process.Pls.refresh my memory on this equation: y-2+3y=10

Mathematics
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-2+4y=10 4y=12 y=3
Pretend y is x.
It's just a different variable.

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combine like terms, add 2 to both sides to get the y alone, divide by 4
Unless, however, the problem is parametric, in which case the equation is used to find the y coordinate. The x equation is treated the same way.
Can you type out the whole process for me to see?
Solving for y?
I believe so.
\[Y-2+3Y=10\] \[Y+3y=10-2=8\] \[4y=8\] \[Y=8div4\] \[Y=2\]
Does that make sense?
I have to look it over before I can say whether or not it makes sense.
So the Y is equal to 1 that made it 4?
Thanks for your help!
No, it equals 2.
In order for the equation to hold true.
No,what I meant was : Y+ 3y = 4?
No, y+3y=8 because you subtract 2 from 10 first, getting 8. So, y+3y=8 Which then becomes 4y because you add the y's together, or combine like terms. Then you get y=2, because you divide 8 by 4.
O.k.,thanks for the clarification.
You all set?
Yeah,for now anyways.:)
Haha cool. Glad to help.

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