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anonymous
 5 years ago
O.k. this is a easy one,however,I've forgotten the process.Pls.refresh my memory on this equation:
y2+3y=10
anonymous
 5 years ago
O.k. this is a easy one,however,I've forgotten the process.Pls.refresh my memory on this equation: y2+3y=10

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It's just a different variable.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0combine like terms, add 2 to both sides to get the y alone, divide by 4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Unless, however, the problem is parametric, in which case the equation is used to find the y coordinate. The x equation is treated the same way.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Can you type out the whole process for me to see?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[Y2+3Y=10\] \[Y+3y=102=8\] \[4y=8\] \[Y=8div4\] \[Y=2\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Does that make sense?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I have to look it over before I can say whether or not it makes sense.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So the Y is equal to 1 that made it 4?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Thanks for your help!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0In order for the equation to hold true.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No,what I meant was : Y+ 3y = 4?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No, y+3y=8 because you subtract 2 from 10 first, getting 8. So, y+3y=8 Which then becomes 4y because you add the y's together, or combine like terms. Then you get y=2, because you divide 8 by 4.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0O.k.,thanks for the clarification.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yeah,for now anyways.:)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Haha cool. Glad to help.
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