## anonymous 5 years ago need clarification on solving this equation

1. anonymous

which?

2. anonymous

$y ^{3}-10y ^{3 \over 2}+16=0$

3. anonymous

I got y=2 and y=8 so far..I'm not sure if I need to change this to a fraction or what?

4. anonymous

Try writing the y^(3/2) in another term, suck as x

5. anonymous

if you set x = y^(3/2) you will get x^2-10x+16

6. anonymous

ok. Where do I go from here? :/

7. anonymous

factor the equation for (x-2) (x-8) so you get x=2 and x=8

8. anonymous

and then substitute x = y^(3/2) and then solve

9. anonymous

y^(3/2) = 2 y^(3/2) = 8 y = 2^(2/3) y = 4

10. anonymous

okk gotcha! thanks!