anonymous
  • anonymous
what is mean value theorem? isnt there an equation for it?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
There is like two.. mean value for intergrals and derivatives.. you should google that though
myininaya
  • myininaya
If f is continuous on and differentiable on [a,b], then there is c between a and b such that f'(c)=[f(b)-f(a)]/[b-a]
anonymous
  • anonymous
ha umm ok i should just give the question out cause i got confused with that explanation, f(x)= |(x^2-12)(x^2+4)|, how many numbers in the interval -2

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myininaya
  • myininaya
find f'(x) plug in c find [f(3)-f(-2)]/[3-(-2)] set that =f'(c) and solve for c
anonymous
  • anonymous
um may be a dumb question but how does one do the derivative of an absolute value?
myininaya
  • myininaya
f(x)=|x|=x when x>0 and -x when x<0 and x=0 when x=0 since the left derivative does not equal to right derivative for f'(0) then the derivative does not exist at 0 f'(x)=1 when x>0 and -1 when x<0
myininaya
  • myininaya
f(x)=|x-2|=x-2 when x>2 and -(x-2) when x<2 and 0 when x=2 f'(x)=1 when x>2 and -1 when x<2 the derivative dne at x=2
myininaya
  • myininaya
f(x)=|x+5|=x+5 when x>-5 and -(x+5) when x<-5 and 0 when x=-5 f'(x)=1 when x>-5 and -1when x<-5 derivative dne at x=-5
myininaya
  • myininaya
f(x)=|2x+5|=2x+5 when x>-5/2 and -(2x+5) when x<-5/2 and 0 when x=-5/2 f'(x)= 2 when x>-5/2 and -2 when x<-5/2 f' dne at x=-5/2
myininaya
  • myininaya
hows that?
myininaya
  • myininaya
i'm going to get ready for bed but I will come back for a few minutes if you have questions
anonymous
  • anonymous
yeah imma be studying this over so its fine take your time
myininaya
  • myininaya
back for a short time
anonymous
  • anonymous
ummm..ok i did the derivative and its 2x(x^2+4) + (x^2-12)2x but i couldnt get the hang of the absolute value so i left it like that as if it wasnt there
myininaya
  • myininaya
what is the function?
anonymous
  • anonymous
|(x^2-12)(x^2+4)|
myininaya
  • myininaya
sorry i;m back i had a thing but i will scan what i did
myininaya
  • myininaya
1 Attachment
myininaya
  • myininaya
one correction needed one sec i will scan it again
myininaya
  • myininaya
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myininaya
  • myininaya
the first one is the wrong problem anyways lol
myininaya
  • myininaya
any questions
myininaya
  • myininaya
im tired gn
anonymous
  • anonymous
I was up till 1:30 am still trying to understand this and well i think i got it but in the end we end up having two equations one positive and the other negative right? Also how does one find out if x is less or greater, does it have to be placed on a chart like how you have sqrt of 12 and -12? sorry, slow learner...thank you for your patience

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