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anonymous
 5 years ago
what is mean value theorem? isnt there an equation for it?
anonymous
 5 years ago
what is mean value theorem? isnt there an equation for it?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0There is like two.. mean value for intergrals and derivatives.. you should google that though

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0If f is continuous on and differentiable on [a,b], then there is c between a and b such that f'(c)=[f(b)f(a)]/[ba]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ha umm ok i should just give the question out cause i got confused with that explanation, f(x)= (x^212)(x^2+4), how many numbers in the interval 2<x<3 satisfy the conclusion of the MVT

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0find f'(x) plug in c find [f(3)f(2)]/[3(2)] set that =f'(c) and solve for c

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0um may be a dumb question but how does one do the derivative of an absolute value?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0f(x)=x=x when x>0 and x when x<0 and x=0 when x=0 since the left derivative does not equal to right derivative for f'(0) then the derivative does not exist at 0 f'(x)=1 when x>0 and 1 when x<0

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0f(x)=x2=x2 when x>2 and (x2) when x<2 and 0 when x=2 f'(x)=1 when x>2 and 1 when x<2 the derivative dne at x=2

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0f(x)=x+5=x+5 when x>5 and (x+5) when x<5 and 0 when x=5 f'(x)=1 when x>5 and 1when x<5 derivative dne at x=5

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0f(x)=2x+5=2x+5 when x>5/2 and (2x+5) when x<5/2 and 0 when x=5/2 f'(x)= 2 when x>5/2 and 2 when x<5/2 f' dne at x=5/2

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0i'm going to get ready for bed but I will come back for a few minutes if you have questions

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah imma be studying this over so its fine take your time

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0back for a short time

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ummm..ok i did the derivative and its 2x(x^2+4) + (x^212)2x but i couldnt get the hang of the absolute value so i left it like that as if it wasnt there

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0what is the function?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0sorry i;m back i had a thing but i will scan what i did

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0one correction needed one sec i will scan it again

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0the first one is the wrong problem anyways lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I was up till 1:30 am still trying to understand this and well i think i got it but in the end we end up having two equations one positive and the other negative right? Also how does one find out if x is less or greater, does it have to be placed on a chart like how you have sqrt of 12 and 12? sorry, slow learner...thank you for your patience
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