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anonymous

  • 5 years ago

Determine a. if f has a maximum value or a minimum value; b. the value of x at which the maximum or minimum occurs; c. the maximum or minimum value of f: f(x)=2x^2+3x+2

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  1. myininaya
    • 5 years ago
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    since the coefficient of x^2 is postive then the parabola opens upward so U that means we have a minmum

  2. anonymous
    • 5 years ago
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    Oh, wow, now that made sense...so the first part is that easy..okay, i'm following thoroughly

  3. myininaya
    • 5 years ago
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    f(x)=2(x^2+3x/2)+2 f(x)=2(x^2+3x/2+(3/4)^2)+2-2(3/4)^2 f(x)=2(x+3/4)^2+2-9/8 f(x)=2(x+3/4)^2+7/8 so the max is x=-3/4 the max value is 7/8

  4. anonymous
    • 5 years ago
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    wow...that made sense...not too bad actually

  5. myininaya
    • 5 years ago
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    lol usually people get confused when I add in a weird zero

  6. anonymous
    • 5 years ago
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    I didn't see a weird 0

  7. anonymous
    • 5 years ago
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    lol..thanks again

  8. myininaya
    • 5 years ago
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    ur wecolme

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