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anonymous
 5 years ago
does A=(0.01)(1.1^t/8) have an asymptote?
why or why not?
anonymous
 5 years ago
does A=(0.01)(1.1^t/8) have an asymptote? why or why not?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes A can never equal zero

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but if the graph is always increasing even if it's by very small increments, is it still an asymptote?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the asymptote is horizontal ie A=0 there is no vertical asymptote

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no problem, if you drew it on an axis you would see that the line would never cross the x axis and it would grow without bound forever

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what about something liek p(t)=100(4^t) where the graph would be vertical?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0never ever ever ever ever. it would become very very steep for large values of t but it would never be completly vertical

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so is that called an asymptote because it'll never reach 0. a vertical asymptote?
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