## anonymous 5 years ago I need to verify I have the correct vertex of the following.. f(x)=x^2-x+1 I also am unable to figure out how to get the values from the graphing calculator. Anyone know please?

1. anonymous

to find the vertex you'll have to take x = -b/2a then find f(-b/2a) :)

2. anonymous

so , I have the following: a = 1, b = -1 and x = 1 $x = \frac{1}{2}$ and $f(\frac{1}{2}) = (\frac{1}{2})^2 -\frac{1}{2} + 1 = \frac{3}{4}$ so your vertex is : $(\frac{1}{2}, \frac{3}{4})$ correct me if I'm wrong ^_^

3. anonymous

Wow, that is what I JUST got when I zoomed in my calculator.

4. anonymous

That is wonderful. But on that calculator, how do I find the value?

5. anonymous

hmm, I'm not sure, I've never used a graphing calculator before :) I just simply sketch ^_^

6. anonymous

why don't you sketch it?

7. anonymous

Oh my goodness, thank you . I have been trying to find the vertex formula.

8. anonymous

I did sketch it..

9. anonymous

most welcome :)

10. anonymous

then you can easily plot the vertec from your sketch :)

11. anonymous

vertex*

12. anonymous

Its asks for values such as XMIN, XMAX, XSCL, YMIN, YMAX AND YSCL

13. anonymous

the question? or the graphing calculator?

14. anonymous

IIs on the calculator, but it never changes from -10 or 10..

15. anonymous

those values should show on the calculator..but i have no clue how to find them and it's part of my answer the teacher wants

16. anonymous

lol, I wish I can get my sister here, she uses a graphing calculator , she'll prolly know the answer, but school lol

17. anonymous

I'm sorry :(

18. anonymous

LOL. Thank you for your help. I will figure it out tomorrow..thanks a bunch