anonymous
  • anonymous
I need to verify I have the correct vertex of the following.. f(x)=x^2-x+1 I also am unable to figure out how to get the values from the graphing calculator. Anyone know please?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
to find the vertex you'll have to take x = -b/2a then find f(-b/2a) :)
anonymous
  • anonymous
so , I have the following: a = 1, b = -1 and x = 1 \[x = \frac{1}{2}\] and \[f(\frac{1}{2}) = (\frac{1}{2})^2 -\frac{1}{2} + 1 = \frac{3}{4}\] so your vertex is : \[(\frac{1}{2}, \frac{3}{4})\] correct me if I'm wrong ^_^
anonymous
  • anonymous
Wow, that is what I JUST got when I zoomed in my calculator.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
That is wonderful. But on that calculator, how do I find the value?
anonymous
  • anonymous
hmm, I'm not sure, I've never used a graphing calculator before :) I just simply sketch ^_^
anonymous
  • anonymous
why don't you sketch it?
anonymous
  • anonymous
Oh my goodness, thank you . I have been trying to find the vertex formula.
anonymous
  • anonymous
I did sketch it..
anonymous
  • anonymous
most welcome :)
anonymous
  • anonymous
then you can easily plot the vertec from your sketch :)
anonymous
  • anonymous
vertex*
anonymous
  • anonymous
Its asks for values such as XMIN, XMAX, XSCL, YMIN, YMAX AND YSCL
anonymous
  • anonymous
the question? or the graphing calculator?
anonymous
  • anonymous
IIs on the calculator, but it never changes from -10 or 10..
anonymous
  • anonymous
those values should show on the calculator..but i have no clue how to find them and it's part of my answer the teacher wants
anonymous
  • anonymous
lol, I wish I can get my sister here, she uses a graphing calculator , she'll prolly know the answer, but school lol
anonymous
  • anonymous
I'm sorry :(
anonymous
  • anonymous
LOL. Thank you for your help. I will figure it out tomorrow..thanks a bunch

Looking for something else?

Not the answer you are looking for? Search for more explanations.