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anonymous

  • 5 years ago

I need to verify I have the correct vertex of the following.. f(x)=x^2-x+1 I also am unable to figure out how to get the values from the graphing calculator. Anyone know please?

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  1. anonymous
    • 5 years ago
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    to find the vertex you'll have to take x = -b/2a then find f(-b/2a) :)

  2. anonymous
    • 5 years ago
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    so , I have the following: a = 1, b = -1 and x = 1 \[x = \frac{1}{2}\] and \[f(\frac{1}{2}) = (\frac{1}{2})^2 -\frac{1}{2} + 1 = \frac{3}{4}\] so your vertex is : \[(\frac{1}{2}, \frac{3}{4})\] correct me if I'm wrong ^_^

  3. anonymous
    • 5 years ago
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    Wow, that is what I JUST got when I zoomed in my calculator.

  4. anonymous
    • 5 years ago
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    That is wonderful. But on that calculator, how do I find the value?

  5. anonymous
    • 5 years ago
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    hmm, I'm not sure, I've never used a graphing calculator before :) I just simply sketch ^_^

  6. anonymous
    • 5 years ago
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    why don't you sketch it?

  7. anonymous
    • 5 years ago
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    Oh my goodness, thank you . I have been trying to find the vertex formula.

  8. anonymous
    • 5 years ago
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    I did sketch it..

  9. anonymous
    • 5 years ago
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    most welcome :)

  10. anonymous
    • 5 years ago
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    then you can easily plot the vertec from your sketch :)

  11. anonymous
    • 5 years ago
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    vertex*

  12. anonymous
    • 5 years ago
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    Its asks for values such as XMIN, XMAX, XSCL, YMIN, YMAX AND YSCL

  13. anonymous
    • 5 years ago
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    the question? or the graphing calculator?

  14. anonymous
    • 5 years ago
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    IIs on the calculator, but it never changes from -10 or 10..

  15. anonymous
    • 5 years ago
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    those values should show on the calculator..but i have no clue how to find them and it's part of my answer the teacher wants

  16. anonymous
    • 5 years ago
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    lol, I wish I can get my sister here, she uses a graphing calculator , she'll prolly know the answer, but school lol

  17. anonymous
    • 5 years ago
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    I'm sorry :(

  18. anonymous
    • 5 years ago
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    LOL. Thank you for your help. I will figure it out tomorrow..thanks a bunch

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