cherrilyn 5 years ago Evaluate the integral by completing the square and using trig substitution. After completing the square I got (x+3)^2-3 but I don't know what to do next

1. Yuki

you have to give us what we are supposed to integrate is it $\int\limits[(x+3)^2-2]dx$?

2. anonymous

no, its unlikely to be that ^ lol it will be something with a division. my guess is : $1/ [ (x+3)^2 -3]$

3. anonymous

or possibly the above with a sqrt on the denominator, its a standard integral

4. cherrilyn

$\int\limits_{}^{} dx \div (x ^{2} + 6x + 6 )^{2}$

5. cherrilyn

oh no... Sorry.. the equation is $\int\limits_{}^{} dx / (x ^{2} + 6x + 6)^{2}$