## anonymous 5 years ago find integral of {sec(x)tan(x)/sec(x)-1

1. Yuki

could you write it out using the equation button?

2. anonymous

$\int\limits \frac{\sec(x) \tan(x)}{\sec(x) -1} dx$?

3. anonymous

so du = sec(x)tan(x) ^_^ and you'll get the following: $\int\limits \frac{1}{u} du = \ln|u| + c = \ln|\sec(x)-1| + c$let u = sec(x) -1 Correct me if I'm wrong ^_^

4. anonymous

oh dear, the steps are messed up , I apologize

5. anonymous

thank you im trying to figure it out ;-)

6. anonymous

oh, you're welcome, let me know if you don't get it :)