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anonymous
 5 years ago
Find the domain of the function p(x)x^2x+1
What is the domain of p?
anonymous
 5 years ago
Find the domain of the function p(x)x^2x+1 What is the domain of p?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Can you specify the p function clearer please. The way that is now doesnt make any sense to me.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Is this the equation my friend?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The only thing I can tell you is that the answer is either x is a real number and x= with a line through it or x is a real number or x is arel number and > 0 or x is a real number x= with a line through it 1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry the first one should have a0 at the end

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes it is one equation

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Take a look to the graph I attached. The domain goes from 0 to + infinite: Im trying to figure out how to mathematically get the answer. Please be pacient

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I could not figure it I had no clue how to begin to find the answer to this question

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0why you men by a "()" at the end?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0p(x)=x^(2x+1) is this the function?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x is a real number x =(with a line through it) 0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah I understand that. What it is not clear for me is if the function p. Is p(x)=x^(2x+1) the function? Please write it down again

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but were is the = sign? or this expression equated to zero? like this: p(x)x^2x+1=0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You need an = sign dude

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0there is no equal sign

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok. Im gonna suppose the = sign is at the end.Now I want you to tell me what of the two following equations is your equation. The way you write (without parenthesis) in not clear. a) p(x)x^(2x+1) b) p(x)x^(2x)+1 choose one. a or be

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0emun, sorry for just coming into the question like this... but i really think that the function would be p(x) = x^(2x) + 1 i have yet to see a question that gives the function as part of the equation as you suggested

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah that was what I thought. No problem

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0as for the domain, there's no mathematical operations to be done to put simply, you just look at the equation, pay special attention to the places where x is present. is there any values of x that would make the function undefined?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The function have the shape that is shown in the graph attached. You were right. The domain for this function goes like this: (infinity,0)U(0,+infinity) How do you find it? The most convenient way is to give x some values. The values I gave p are. p(3)=0.99 p(2)=0.937 p(1)=0 Until now we have found that x>0 is part of the domain => (0,+infinity) if you set x=0, we get p(0)=something divided by 0 = not a real number. So 0 is not part of the domain. Lets go a little bit to the left. P(1)=something very small p(2)=somithins smalle even. p for negative number exist anyway. So we can consider the negatives numbers as part of the domain of the function, that is (infinity,0). Any question?
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