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anonymous
 5 years ago
if you travel to work at 30mph and go home by 40 mph, what is the average rate for the entire trip?
anonymous
 5 years ago
if you travel to work at 30mph and go home by 40 mph, what is the average rate for the entire trip?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I am totally lost, because there is no distance or time given

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0are you there? I appreciate the help

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That's all the problem gives you?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes, it is why I am so frustated

Regan
 5 years ago
Best ResponseYou've already chosen the best response.1(30mph*t1+40mph*t2)/(t1+t2) which reads total distance over total time thats all i can think of

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah, regan's answer looks right

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if you aren't given time or distance

Regan
 5 years ago
Best ResponseYou've already chosen the best response.1and 30mph*t1=40mph*t2 this may also help

Regan
 5 years ago
Best ResponseYou've already chosen the best response.130mph*t1*2/t1+30mph*t1/40mph

Regan
 5 years ago
Best ResponseYou've already chosen the best response.1t1(30*2) numerator t1(1+3/4) denominator

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how'd you get that lol :)

Regan
 5 years ago
Best ResponseYou've already chosen the best response.1ok using 30mph*t1=40mph*t2 i said 30mph*t1+30mph*t1=30mph*t1+40mph*t2 in the denominator and t1+t2=t1+(30/40)*t1 in the numerator so we have (t1(30*2))/(t1(1+3/4)) numerator/denominator however they both have been written in terms of t1 therefore can cancel to get 30*2/1.75 which equals 34.29

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah it does , thank you so much
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