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anonymous

  • 5 years ago

how to solve equation ie A^4+7a^2+1(3)

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  1. anonymous
    • 5 years ago
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    is it supposed to be A and a? and that last part is just 1 * 3?

  2. anonymous
    • 5 years ago
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    \[a ^{4}+7a ^{2}+3\] is that the equation?

  3. anonymous
    • 5 years ago
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    yea

  4. anonymous
    • 5 years ago
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    use quad formula a= (-i) sqrt[(7 - Sqrt[37])/2], i Sqrt[(7 - Sqrt[37])/2], (-i) Sqrt[(7 + Sqrt[37])/2], i Sqrt[(7 + Sqrt[37])/2]

  5. anonymous
    • 5 years ago
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    it is a parabola with a vertex at (0,3) and never crosses the x-axis so no solutions (roots, zeroes)

  6. anonymous
    • 5 years ago
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    are you sure that this equation has no solution

  7. anonymous
    • 5 years ago
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    btm is right, there are no REAL solutions notice how all the values i provided has i in it? it's imaginery

  8. anonymous
    • 5 years ago
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    are you graphing to find a solution...what section/concept is it

  9. anonymous
    • 5 years ago
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    actually im a student of accoutant .today was our test and in that test this was the question .to solve this equation

  10. anonymous
    • 5 years ago
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    can u please tell me the reason why it is unsolveable

  11. anonymous
    • 5 years ago
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    it is unsolvable by graphing because it will not touch the x axis but mathematically (ie using the quadratic formula) you will be able to get the roots they are the real roots, they're imaginary roots

  12. anonymous
    • 5 years ago
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    thanks buddy

  13. anonymous
    • 5 years ago
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    sure thing

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spraguer (Moderator)
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