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anonymous
 5 years ago
how to solve equation ie A^4+7a^2+1(3)
anonymous
 5 years ago
how to solve equation ie A^4+7a^2+1(3)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is it supposed to be A and a? and that last part is just 1 * 3?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[a ^{4}+7a ^{2}+3\] is that the equation?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0use quad formula a= (i) sqrt[(7  Sqrt[37])/2], i Sqrt[(7  Sqrt[37])/2], (i) Sqrt[(7 + Sqrt[37])/2], i Sqrt[(7 + Sqrt[37])/2]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it is a parabola with a vertex at (0,3) and never crosses the xaxis so no solutions (roots, zeroes)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0are you sure that this equation has no solution

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0btm is right, there are no REAL solutions notice how all the values i provided has i in it? it's imaginery

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0are you graphing to find a solution...what section/concept is it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0actually im a student of accoutant .today was our test and in that test this was the question .to solve this equation

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can u please tell me the reason why it is unsolveable

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it is unsolvable by graphing because it will not touch the x axis but mathematically (ie using the quadratic formula) you will be able to get the roots they are the real roots, they're imaginary roots
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