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- anonymous

If you graph f(x)= x^2 + y^2 then it is a circle but then how would you graph the square root of f(x)?

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- anonymous

- katieb

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- anonymous

how would you go about graphing it*

- anonymous

but f(x)= x^2 + y^2 isn't a circle

- anonymous

i'm pretty sure f(x)= x^2 + y^2 is a circle...
the square root of f(x) is half a circle
if it's positive sqrt of f(x), it'll be the top half of the circle
if it's negative, it will be the bottom half.

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- anonymous

what would be the radius?

- anonymous

good point, i didn't catch that
uzma right
but i think the point of the question is to understand that the square roots is half a circle
so you need a value for f(x), otherwise, as uzma said, it's not a circle

- anonymous

yes :)

- anonymous

it must be x^2 + y^2= costant, then centre is (0,0) and radius is sqrt(constant)

- anonymous

or we can have the general eq
x^2 +y^2 +2fx+2gy +c=0

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