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anonymous
 5 years ago
If you graph f(x)= x^2 + y^2 then it is a circle but then how would you graph the square root of f(x)?
anonymous
 5 years ago
If you graph f(x)= x^2 + y^2 then it is a circle but then how would you graph the square root of f(x)?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how would you go about graphing it*

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but f(x)= x^2 + y^2 isn't a circle

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i'm pretty sure f(x)= x^2 + y^2 is a circle... the square root of f(x) is half a circle if it's positive sqrt of f(x), it'll be the top half of the circle if it's negative, it will be the bottom half.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what would be the radius?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0good point, i didn't catch that uzma right but i think the point of the question is to understand that the square roots is half a circle so you need a value for f(x), otherwise, as uzma said, it's not a circle

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it must be x^2 + y^2= costant, then centre is (0,0) and radius is sqrt(constant)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0or we can have the general eq x^2 +y^2 +2fx+2gy +c=0
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