anonymous
  • anonymous
If you graph f(x)= x^2 + y^2 then it is a circle but then how would you graph the square root of f(x)?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
how would you go about graphing it*
anonymous
  • anonymous
but f(x)= x^2 + y^2 isn't a circle
anonymous
  • anonymous
i'm pretty sure f(x)= x^2 + y^2 is a circle... the square root of f(x) is half a circle if it's positive sqrt of f(x), it'll be the top half of the circle if it's negative, it will be the bottom half.

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anonymous
  • anonymous
what would be the radius?
anonymous
  • anonymous
good point, i didn't catch that uzma right but i think the point of the question is to understand that the square roots is half a circle so you need a value for f(x), otherwise, as uzma said, it's not a circle
anonymous
  • anonymous
yes :)
anonymous
  • anonymous
it must be x^2 + y^2= costant, then centre is (0,0) and radius is sqrt(constant)
anonymous
  • anonymous
or we can have the general eq x^2 +y^2 +2fx+2gy +c=0

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