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anonymous

  • 5 years ago

If you graph f(x)= x^2 + y^2 then it is a circle but then how would you graph the square root of f(x)?

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  1. anonymous
    • 5 years ago
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    how would you go about graphing it*

  2. anonymous
    • 5 years ago
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    but f(x)= x^2 + y^2 isn't a circle

  3. anonymous
    • 5 years ago
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    i'm pretty sure f(x)= x^2 + y^2 is a circle... the square root of f(x) is half a circle if it's positive sqrt of f(x), it'll be the top half of the circle if it's negative, it will be the bottom half.

  4. anonymous
    • 5 years ago
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    what would be the radius?

  5. anonymous
    • 5 years ago
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    good point, i didn't catch that uzma right but i think the point of the question is to understand that the square roots is half a circle so you need a value for f(x), otherwise, as uzma said, it's not a circle

  6. anonymous
    • 5 years ago
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    yes :)

  7. anonymous
    • 5 years ago
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    it must be x^2 + y^2= costant, then centre is (0,0) and radius is sqrt(constant)

  8. anonymous
    • 5 years ago
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    or we can have the general eq x^2 +y^2 +2fx+2gy +c=0

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spraguer (Moderator)
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