anonymous
  • anonymous
Find f-1(x). Sketch the graphs of y=f(x) and y=f-1(x) on the same coordinate axes. (Note: the -1 after the f, is up top where the exponent usually is): Answer for: f(x)=3x-4 Please help. I'm lost.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
If you are in like a beginner's level course, they want you to get a few values, like x=0, plug in 0 in f(x) and it will give you y.
anonymous
  • anonymous
This is college Algebra. I'm still lost though; it's been a long time.
anonymous
  • anonymous
Need to get credits for the military in order to get promoted; however I never use this stuff in my line of work. lol

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More answers

anonymous
  • anonymous
Start finding one point. x=0, therefore y=3(0)-4
anonymous
  • anonymous
Can you pleas tell me what the little -1 is after F? This book is horrible which is why I have to get outside resources. I've even looked at purplemath.com so i got good resources.
anonymous
  • anonymous
Okay, I got that first part. You plugged the 0 into the 3X part.
anonymous
  • anonymous
I have a graphing calculator as well as an Algebra program that I can plug in graphs; however I really need to learn how it's done; not just get by.
anonymous
  • anonymous
The little -1 is called the inverse function. In this case set y=3x-4 and solve for x
anonymous
  • anonymous
When I want to enter the little inverse function into a graphing calculator however, how to do I even enter that?
anonymous
  • anonymous
x=y+4/3?
anonymous
  • anonymous
There is an inverse function\[x^{-1}\] but it is used for inverse of simple numbers may not work for an algebraic function. What they are asking is simple enough to do manually. Graph it only to double check your work.
anonymous
  • anonymous
Don't panic go to local community college. They have this thing called a math lab. Ask for a tutor. An hour a few times a week would work wonders.
anonymous
  • anonymous
I sure will. I just need to figure out these last two problems for the work is due today and I've been working so hard all week ...on each lesson...
anonymous
  • anonymous
And midterms this week too...wow..

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