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anonymous
 5 years ago
I am still looking for some help please. I am completely confused..
Find f1(x) (THE 1 IS AN INVERSE FUNCTION). Sketch the graphs of y=f(x) and y=f1(x) on the same coordinate axes.
Answer for f(x)=3x4
I am not understanding how this works...
anonymous
 5 years ago
I am still looking for some help please. I am completely confused.. Find f1(x) (THE 1 IS AN INVERSE FUNCTION). Sketch the graphs of y=f(x) and y=f1(x) on the same coordinate axes. Answer for f(x)=3x4 I am not understanding how this works...

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0for the inverse switch x and y so your original formula is y = 3x  4 now switch x and y for inverse x = 3y  4 this is a correct answer but teachers usually want it in y = mx + b form so y = (x + 4)/3 would be your answer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What if I tried f(x)=x^3+1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0How are exponents carried over in these types of equations?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Isolate it one side. The inverse of cube is the cube root

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0To sketch the graph take the values of x = 3 to x = 3 and substitute into the equation f(x) = 3x +4 and plot the point therefore when x = 3 f(x) or y = 4 when x= 2 f(x) or y = 2 when x =1 f(x) or y = 1 when x = 0 y = 4 when x = 1 y = 7 when x = 2 y =10 when x = 3 y = 11 plot those points then do the same for the inverse function .
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