anonymous
  • anonymous
can someone please help me solve 15x^4-14x^2+3=0
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
15x4-9x2-5x2 +3=0 3x2(5x2-3)-(5x2-3)=0
anonymous
  • anonymous
(3x2-1)(5x2-3)=0
anonymous
  • anonymous
(3x^2-1)(5x^2-3)=0 +-Sqrt[3/5] +-1/Sqrt[3]

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anonymous
  • anonymous
u r cute
anonymous
  • anonymous
Thanks and how am i suppose to write that answer
anonymous
  • anonymous
\[x \in\left\{\pm \sqrt{3/5}; \pm1/\sqrt{3} \right\}\]
anonymous
  • anonymous
15x4-9x2-5x2 +3=0 3x2(5x2-3)-(5x2-3)=0 (3x2-1)(5x2-3)=0 3x2-1=0 , 5x2-3=0 x2=1/3, x2=3/4 x=+-1/sqrt3 , x=+- sqrt3 /2
anonymous
  • anonymous
where r u from?
anonymous
  • anonymous
sc
anonymous
  • anonymous
sc?
anonymous
  • anonymous
Scotland?
anonymous
  • anonymous
and u are from
anonymous
  • anonymous
south cakcalaki
anonymous
  • anonymous
australia
anonymous
  • anonymous
whoops :) Im from Czech republic :)
anonymous
  • anonymous
what grade r u in?
anonymous
  • anonymous
me or dollar?
anonymous
  • anonymous
both
anonymous
  • anonymous
I dont know your educational system. Im on hight school and im finishing it on 2012
anonymous
  • anonymous
ankur u mean -1 sq root 3, and -3/2
anonymous
  • anonymous
college
anonymous
  • anonymous
x=1/sqrt3, +-1/sqrt3 , x= sqrt3 /2, - sqrt3 /2
anonymous
  • anonymous
you have error there
anonymous
  • anonymous
it is sqrt(3/5) not (3/4)
anonymous
  • anonymous
serychj im confused on which answer to put
anonymous
  • anonymous
mine is correct :) his have error in one line before end: 5x2-3=0 x2=3/4 -> error x^2=3/5
anonymous
  • anonymous
sorry guys but all the answers were wrong after a couple of tries it generates the correct answer and it was -sq3/3,sq3/3,and -sq15/5,sq15/5 thanks anyway
anonymous
  • anonymous
check this: http://www.wolframalpha.com/input/?i=15x^4-14x^2%2B3%3D0 your wrong

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