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anonymous

  • 5 years ago

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  1. anonymous
    • 5 years ago
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    evaluated!

  2. anonymous
    • 5 years ago
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    \[\int\limits_{1}^{2} (7 - 2/x + 7/x^3) dx\]

  3. anonymous
    • 5 years ago
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    will I find u and du with this problem

  4. anonymous
    • 5 years ago
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    This one integrate term by term.

  5. anonymous
    • 5 years ago
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    \[7x - 2\ln|x| - 7/4x ^{4}\] evaluated at x = 2 and subtract off what you get when you evaluate at x = 1.

  6. anonymous
    • 5 years ago
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    will it better to bring the x on top ex. 2/x to 2x^-1

  7. anonymous
    • 5 years ago
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    7x−2ln|x|−7x^-2 /-2 =7x−2ln|x|−7+7/2 x^2

  8. anonymous
    • 5 years ago
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    now I am confussed. I am having alot of trouble with these problems. When I look at them I do not know where to start. I do not know what to do next

  9. anonymous
    • 5 years ago
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    Just put the integral sign in fron of each term and integrate term by term. No confusion.

  10. anonymous
    • 5 years ago
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    easy to say if you understand it. where did the -7 come from then +7/2x^2

  11. anonymous
    • 5 years ago
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    The last item \[(7 \ x ^{3}) \] is on the bottom. By convention you rewrite it \[7x ^{-3}\]. When you integrate that you would get a negative term.

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spraguer (Moderator)
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