Evaluate:

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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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evaluated!
\[\int\limits_{1}^{2} (7 - 2/x + 7/x^3) dx\]
will I find u and du with this problem

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This one integrate term by term.
\[7x - 2\ln|x| - 7/4x ^{4}\] evaluated at x = 2 and subtract off what you get when you evaluate at x = 1.
will it better to bring the x on top ex. 2/x to 2x^-1
7x−2ln|x|−7x^-2 /-2 =7x−2ln|x|−7+7/2 x^2
now I am confussed. I am having alot of trouble with these problems. When I look at them I do not know where to start. I do not know what to do next
Just put the integral sign in fron of each term and integrate term by term. No confusion.
easy to say if you understand it. where did the -7 come from then +7/2x^2
The last item \[(7 \ x ^{3}) \] is on the bottom. By convention you rewrite it \[7x ^{-3}\]. When you integrate that you would get a negative term.

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