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anonymous
 5 years ago
Evaluate:
anonymous
 5 years ago
Evaluate:

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{1}^{2} (7  2/x + 7/x^3) dx\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0will I find u and du with this problem

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0This one integrate term by term.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[7x  2\lnx  7/4x ^{4}\] evaluated at x = 2 and subtract off what you get when you evaluate at x = 1.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0will it better to bring the x on top ex. 2/x to 2x^1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.07x−2lnx−7x^2 /2 =7x−2lnx−7+7/2 x^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now I am confussed. I am having alot of trouble with these problems. When I look at them I do not know where to start. I do not know what to do next

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Just put the integral sign in fron of each term and integrate term by term. No confusion.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0easy to say if you understand it. where did the 7 come from then +7/2x^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The last item \[(7 \ x ^{3}) \] is on the bottom. By convention you rewrite it \[7x ^{3}\]. When you integrate that you would get a negative term.
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