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prettychicka45

  • 3 years ago

if a club has 13 memebers how many different arragments of president, vice president, and secreary are possible

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  1. ankur504
    • 3 years ago
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    4896?

  2. prettychicka45
    • 3 years ago
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    nope

  3. heisenberg
    • 3 years ago
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    You would have the number of ways to choose 3 from 13: C(13, 3) Then there are 3! ways to arrange them. so C(13,3) * 3! are you familiar with that 'C'ombinatorics function?

  4. heisenberg
    • 3 years ago
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    also known as the 'Binomial coefficient' \[C(n,r) = \frac{n!}{r! * (n-r)!}\]

  5. heisenberg
    • 3 years ago
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    can you solve? I get '1716'

  6. prettychicka45
    • 3 years ago
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    thank you

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