## prettychicka45 Group Title if a club has 13 memebers how many different arragments of president, vice president, and secreary are possible 3 years ago 3 years ago

1. ankur504

4896?

2. prettychicka45

nope

3. heisenberg

You would have the number of ways to choose 3 from 13: C(13, 3) Then there are 3! ways to arrange them. so C(13,3) * 3! are you familiar with that 'C'ombinatorics function?

4. heisenberg

also known as the 'Binomial coefficient' $C(n,r) = \frac{n!}{r! * (n-r)!}$

5. heisenberg

can you solve? I get '1716'

6. prettychicka45

thank you