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if a club has 13 memebers how many different arragments of president, vice president, and secreary are possible

Mathematics
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4896?
nope
You would have the number of ways to choose 3 from 13: C(13, 3) Then there are 3! ways to arrange them. so C(13,3) * 3! are you familiar with that 'C'ombinatorics function?

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Other answers:

also known as the 'Binomial coefficient' \[C(n,r) = \frac{n!}{r! * (n-r)!}\]
can you solve? I get '1716'
thank you

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