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anonymous
 5 years ago
I keep asking for help, but so far no one has been able to help me. Please help; this assignment is due in only a couple of hours now and I can't figure this out.
Find f1(x) (1 is an inverse function). Sketch the graphs of y=f(x) and y=f1(x) on the same coordinate axes. Answer for f(x)=2x+3 The answer I have is f1(x)=x3/2
y=2x+3
x=2y+3
x3=2y
x/23/2=y
I have the answer above, but do not understand how to get the y=axes part of the graph. What part of it..
Basically, when i plug in y=2x+3, I get part of the graph, but not the other side and I do not want to get these wrong.
anonymous
 5 years ago
I keep asking for help, but so far no one has been able to help me. Please help; this assignment is due in only a couple of hours now and I can't figure this out. Find f1(x) (1 is an inverse function). Sketch the graphs of y=f(x) and y=f1(x) on the same coordinate axes. Answer for f(x)=2x+3 The answer I have is f1(x)=x3/2 y=2x+3 x=2y+3 x3=2y x/23/2=y I have the answer above, but do not understand how to get the y=axes part of the graph. What part of it.. Basically, when i plug in y=2x+3, I get part of the graph, but not the other side and I do not want to get these wrong.

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nowhereman
 5 years ago
Best ResponseYou've already chosen the best response.0Actually the graph of f:x↦y is already the graph of f^{1}:y↦x too. But I guess they want you to mirror it at the line {(x,y)  x=y} so that the axis are being interchanged.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Do you know what equations I should be entering to get the right graphs, considering they are expecting the 2

nowhereman
 5 years ago
Best ResponseYou've already chosen the best response.02x+3 and (x3)/2 I guess.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what are you entering this in...graphing calculator? you could graph it by hand

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I can use the graphing calculator; however I am using the Algebra Program called Bagatrix  College Algebra solved which is much easier

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok, well you have the correct equations

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Let me try what you have and see

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0y=2x+3 does show up properly; however nothing else I plug in works. This was just a practice question; so I have the graph to go off of, but I can't get the other equation right for some reason

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Because calculators are set up for y= type. But like the other guy said, you are working with simple graphs, just do it by hand.
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