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anonymous
 5 years ago
Find the indicated integral using the method of substitution.
3t[(t^2+8)^1/2] dt
anonymous
 5 years ago
Find the indicated integral using the method of substitution. 3t[(t^2+8)^1/2] dt

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1trig substitution? or otherwise?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i think he means regular sub

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0there's no need for a trig id here

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1but, but..... i wanna do a trig ;)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0rofllls, do the one from this afternoon!

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.13t sqrt(t^2 +8); u = t^2 + 8; du = 2t dx; dx = du/2t

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.13t sqrt(u) du  = (3/2) sqrt(u) du 2t

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.03t[(t^2+8)^1/2] dt u = t^2 + 8 du = 2t dt \[\frac{3}{2}\int\limits_{}^{}u^{\frac{1}{2}}du = \frac{3}{2}*\frac{2}{3} u ^{\frac{3}{2}} = (t^2 + 8)^{\frac{3}{2}}\]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1(3/2) [S] u^(1/2) du (3/2) (2/3) u^(3/2) = u^(3/2)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1yes you do :) and i added a dx for some reason ;)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it's just variables...i'm used to dx also =/ i hate the fact that they switch up variables...
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