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anonymous

  • 5 years ago

can someone help me find the solutions for this problem please?

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  1. anonymous
    • 5 years ago
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    \[(3x+8)^{2}-4(3x+8)-77=0\]

  2. amistre64
    • 5 years ago
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    its a disguised quadratix; just substitute a = 3x+8 a^2 -4a -77 = 0

  3. amistre64
    • 5 years ago
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    (a-11)(a+7)

  4. amistre64
    • 5 years ago
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    a = 11 or a = -7 11 = 3x + 8 or -7 = 3x + 8

  5. anonymous
    • 5 years ago
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    I actually got to the second step there. Just not sure where to go from there

  6. amistre64
    • 5 years ago
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    11 - 8 = 3x 3 = 3x x = 1

  7. amistre64
    • 5 years ago
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    -7 -8 = 3x -15 = 3x x = -5

  8. anonymous
    • 5 years ago
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    okk. yeah this was simpler than I thought. So the answer just comes to 11 and -7?

  9. amistre64
    • 5 years ago
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    the answer for "a" is 11 and -7; but use that to figure out "x" a = 3x +8 becomes 11 = 3x+8 and -7 = 3x+8.....solve for x

  10. anonymous
    • 5 years ago
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    hmm okay. Just to make sure I understand what the next step looks like could you show me?

  11. amistre64
    • 5 years ago
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    you mean more than the two times I jsut did :)

  12. anonymous
    • 5 years ago
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    I think one of them is 1..

  13. anonymous
    • 5 years ago
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    sorry. I'm a visual learner and I want to make sure i'm doing it right :)

  14. amistre64
    • 5 years ago
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    we substituted a variable for (3x+8); right? I used a = 3x+8 we found that a = 11 and a = -7; so use that for solving for x. 11 = 3x+8 11-8 = 3x 3 = 3x x = 1

  15. amistre64
    • 5 years ago
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    a = -7 -7 = 3x+8 -7-8 = 3x -15=3x x = -5

  16. anonymous
    • 5 years ago
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    okk that makes sense. I guess there were most steps than I thought. So now the answers are 1 and -5 I take it? Unless this problem never ends..

  17. anonymous
    • 5 years ago
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    more*

  18. amistre64
    • 5 years ago
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    :) x = 1 and x = -5 are the solutions to the problem :)

  19. anonymous
    • 5 years ago
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    Thanks so much

  20. amistre64
    • 5 years ago
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    youre welcome :)

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