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anonymous
 5 years ago
Find f1(x)
***the 1 is an inverse function, not negative 1***
Sketch the graphs of y=f(x) and y=f1(x)
Equation is: f(x)=2x+3
anonymous
 5 years ago
Find f1(x) ***the 1 is an inverse function, not negative 1*** Sketch the graphs of y=f(x) and y=f1(x) Equation is: f(x)=2x+3

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dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.0y = 2x +3 what is slope? what is yintercept?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you can find the slope of the line by taking the derivitive of your function, f'(x)=2 but with out any known points i don't think there is a way to plug your findings back into a graphable line equation. unless you looking for a straight line that goes across y=2x, something to think about i guess. hope this helps a bit

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the slope of a straight line is its slope :) 2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the inverse of a function is when you transpose x and y then solve for y

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yea i messed up putting the x into my y=2 equation

dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.0ok yintercept is 3 so go to graph and plot point on (0,3) slope is 2 (rise/run) so from (0,3) go up 2 and over 1(2,4) repeat to get more points do the same thing for inverse funtion y=x/2  3/2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0f(x) = y = 2x+3 f^1(x) = x = 2y+3 f^1(x) = y = (x3)/2

dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.0y=x/2  3/2 start at (0,3/2) go up 1 over 2 (2,1/2)
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