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anonymous

  • 5 years ago

can someone please tell me how to solve this differential equation. y^6 + y = 0 . :(

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  1. dumbcow
    • 5 years ago
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    where is dy/dx

  2. anonymous
    • 5 years ago
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    dy/dx has not been given .this is a question related to higher order linear equations.

  3. anonymous
    • 5 years ago
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    i am unable to figure out how to find the roots , please help if you can

  4. dumbcow
    • 5 years ago
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    im not sure if you solve this for y y(y^5+1)=0 y=0 y=-1

  5. anonymous
    • 5 years ago
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    http://tutorial.math.lamar.edu/Classes/DE/HOHomogeneousDE.aspx

  6. anonymous
    • 5 years ago
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    its something of this sort :S But i'm unable to figure out how to solve it for degree 6

  7. dumbcow
    • 5 years ago
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    oh ok thats not y^6 thats really dy/dx ^6 sorry i only took up to first order DE

  8. dumbcow
    • 5 years ago
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    look at example 5 on the link you gave me, that seems to match your problem you would have r^6 = -1 r = (-1)^1/6

  9. anonymous
    • 5 years ago
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    ohh ok i kinda get it..In place of pie-by-4 and pie-by-2 , there will be pie-by-3 and pie-by-6. Am i right ?

  10. dumbcow
    • 5 years ago
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    i think so but not positive sorry

  11. anonymous
    • 5 years ago
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    oh its ok thanks :)

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spraguer (Moderator)
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