can someone please tell me how to solve this differential equation. y^6 + y = 0 . :(

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can someone please tell me how to solve this differential equation. y^6 + y = 0 . :(

Mathematics
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where is dy/dx
dy/dx has not been given .this is a question related to higher order linear equations.
i am unable to figure out how to find the roots , please help if you can

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im not sure if you solve this for y y(y^5+1)=0 y=0 y=-1
http://tutorial.math.lamar.edu/Classes/DE/HOHomogeneousDE.aspx
its something of this sort :S But i'm unable to figure out how to solve it for degree 6
oh ok thats not y^6 thats really dy/dx ^6 sorry i only took up to first order DE
look at example 5 on the link you gave me, that seems to match your problem you would have r^6 = -1 r = (-1)^1/6
ohh ok i kinda get it..In place of pie-by-4 and pie-by-2 , there will be pie-by-3 and pie-by-6. Am i right ?
i think so but not positive sorry
oh its ok thanks :)

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