anonymous
  • anonymous
someone help me please !!!!! :(
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
what do you need help with
anonymous
  • anonymous
writing polynomial functions of least degree with intergral coeffiecients that has the given zeros ?
anonymous
  • anonymous
you gotta give all the info before someone can help you

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anonymous
  • anonymous
3 , 5 , -5
anonymous
  • anonymous
that is all that is on my paper .i just typed what my directions said
anonymous
  • anonymous
that is at least a degree 3 poly (x-3)(x-5)(x+5)
anonymous
  • anonymous
(x-3)(x^2 -25) x^3 -3x^2 -25x +75
anonymous
  • anonymous
ok so next what do i do ?
anonymous
  • anonymous
Suppose you need to write a polynomial function of 6, 2i with intergral coeffiecients that has the given zeros then X-6 is the polynomial with least degree and 6 as zero. X=2i --> X^2=-4 --> X^2+4=0 --> X^2+4 is the polyn. with least degree and 2i as zero. ---> (X-6)(X^2+4)=X^3-6X^2+4X-24 is solution
anonymous
  • anonymous
you write down your three roots like this: (x-3)(x-5)(x+5) ; then multiply them together
anonymous
  • anonymous
im lost . i got \[x ^{2} + 15x\] thats all i have so far .
anonymous
  • anonymous
thats not correct :)
anonymous
  • anonymous
lol ok so what is correct then ?
anonymous
  • anonymous
what do you have as the "root" factors of the problem?
anonymous
  • anonymous
how do you take: x = 3,5,-5 and make root factors?
anonymous
  • anonymous
x then the opposite of the number.. thats what my teacher said
anonymous
  • anonymous
(3+a) = 0 (5+b) = 0 (-5+c) = 0 solve for a b and c and use them like this: (x+a)(x+b)(x+c)
anonymous
  • anonymous
thats right, the opposite of the numbers...
anonymous
  • anonymous
what do you get as your root factors then?
anonymous
  • anonymous
uhm .... lol im sorry but i have ( NO ] clue
anonymous
  • anonymous
root factors is a term im using that has no real mathmatical value except for what I use it for :) root factors, by me, are the (x....)(x......)(x......) things that polys factor down into; does that make sense? x^2 +7x +12 factors into: (x+4)(x+3) <---- root factors are these things
anonymous
  • anonymous
ooooooooooooooooo yea . when you factor .. i know that .. like to factor \[x ^{2} + 5 +14\] wouldnt that be (x+7)(x+2)
anonymous
  • anonymous
thats right :) except for the typos :)
anonymous
  • anonymous
or i mean -14 and then (x+7)(x-2)
anonymous
  • anonymous
:) you should really be my new tutor . lol i understand you more than the rest
anonymous
  • anonymous
the root factor of x=-7 is: (x+7) the root factor of x=4 is: (x-4) the root factor of x=2 is: (x-2)
anonymous
  • anonymous
the root factor of x=3 is: ?? the root factor of x=5 is: ?? the root factor of x=-5 is: ??
anonymous
  • anonymous
thr root factor of x=3 is: (x-3) the root factor of x-5 is: (x+5) the root factor of x=-5 is: (x+5) :) right ?
anonymous
  • anonymous
very good :) now lets multiply those root factors together :)
anonymous
  • anonymous
(x-3)(x+5) = xx -3x +5x -15 = x^2 +2x -15 right?
anonymous
  • anonymous
xx ? n
anonymous
  • anonymous
i mean xx ?
anonymous
  • anonymous
xx means x*x mean x^2
anonymous
  • anonymous
ooooo sorry :) ok im following you again
anonymous
  • anonymous
(x-5)(x^2 +2x -15) = xxx +2xx -15x -5xx -10x +75 : x^3 -3x^2 -25x +75 .... if im seeing it right :)
anonymous
  • anonymous
and its good ;)
anonymous
  • anonymous
lol how old are you ? you are a genius at this
anonymous
  • anonymous
as long as you turn it into your root factors; and keep track of your multiplying, its simple enough :)
anonymous
  • anonymous
....old :)
anonymous
  • anonymous
lol you seem young too me . haha

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