- anonymous

someone help me please !!!!! :(

- chestercat

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- anonymous

what do you need help with

- anonymous

writing polynomial functions of least degree with intergral coeffiecients that has the given zeros ?

- anonymous

you gotta give all the info before someone can help you

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## More answers

- anonymous

3 , 5 , -5

- anonymous

that is all that is on my paper .i just typed what my directions said

- anonymous

that is at least a degree 3 poly
(x-3)(x-5)(x+5)

- anonymous

(x-3)(x^2 -25)
x^3 -3x^2 -25x +75

- anonymous

ok so next what do i do ?

- anonymous

Suppose you need to write a polynomial function of 6, 2i with intergral coeffiecients that has the given zeros
then
X-6 is the polynomial with least degree and 6 as zero.
X=2i --> X^2=-4 --> X^2+4=0 --> X^2+4 is the polyn. with least degree and 2i as zero.
---> (X-6)(X^2+4)=X^3-6X^2+4X-24 is solution

- anonymous

you write down your three roots like this:
(x-3)(x-5)(x+5) ; then multiply them together

- anonymous

im lost . i got \[x ^{2} + 15x\] thats all i have so far .

- anonymous

thats not correct :)

- anonymous

lol ok so what is correct then ?

- anonymous

what do you have as the "root" factors of the problem?

- anonymous

how do you take: x = 3,5,-5 and make root factors?

- anonymous

x then the opposite of the number.. thats what my teacher said

- anonymous

(3+a) = 0
(5+b) = 0
(-5+c) = 0
solve for a b and c and use them like this:
(x+a)(x+b)(x+c)

- anonymous

thats right, the opposite of the numbers...

- anonymous

what do you get as your root factors then?

- anonymous

uhm .... lol im sorry but i have ( NO ] clue

- anonymous

root factors is a term im using that has no real mathmatical value except for what I use it for :)
root factors, by me, are the (x....)(x......)(x......) things that polys factor down into; does that make sense?
x^2 +7x +12 factors into:
(x+4)(x+3) <---- root factors are these things

- anonymous

ooooooooooooooooo yea . when you factor .. i know that ..
like to factor \[x ^{2} + 5 +14\] wouldnt that be (x+7)(x+2)

- anonymous

thats right :) except for the typos :)

- anonymous

or i mean -14 and then (x+7)(x-2)

- anonymous

:) you should really be my new tutor . lol i understand you more than the rest

- anonymous

the root factor of x=-7 is: (x+7)
the root factor of x=4 is: (x-4)
the root factor of x=2 is: (x-2)

- anonymous

the root factor of x=3 is: ??
the root factor of x=5 is: ??
the root factor of x=-5 is: ??

- anonymous

thr root factor of x=3 is: (x-3)
the root factor of x-5 is: (x+5)
the root factor of x=-5 is: (x+5)
:) right ?

- anonymous

very good :)
now lets multiply those root factors together :)

- anonymous

(x-3)(x+5) = xx -3x +5x -15 = x^2 +2x -15 right?

- anonymous

xx ? n

- anonymous

i mean xx ?

- anonymous

xx means x*x mean x^2

- anonymous

ooooo sorry :) ok im following you again

- anonymous

(x-5)(x^2 +2x -15) = xxx +2xx -15x -5xx -10x +75 :
x^3 -3x^2 -25x +75 .... if im seeing it right :)

- anonymous

and its good ;)

- anonymous

lol how old are you ? you are a genius at this

- anonymous

as long as you turn it into your root factors; and keep track of your multiplying, its simple enough :)

- anonymous

....old :)

- anonymous

lol you seem young too me . haha

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