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try us? lols
won't know till you post the question

\[(\sin \theta-\cos \theta)^{2}=1-2\sin^{2} \theta \cot \theta , Verify?\]

thank you but just give me a second to make sure i got it

sure thing

how did you get to sin^2 - 2sin*cos + cos^2 = 1 - 2sin^2(cos/sin)

where did the 2sin come from specifically

i foiled the left side of the equation
and tangent is equal to sin/cos
so cot is equal to cos/sin

(a - b)^2
a^2 -2ab + b^2
it's foil

does that make sense?

i think im having trouble with the foiling

no problem

hey you have time for another?

sure

Sec^4-tan^4, what trig function is it equal to?

sec is 1/cos

i'm not sure if you can get more simplified than that..

the choices are
A) Sec^2
B) csc
C) tan
D) Sec^2+tan^2
E) sin^2
F) sin*tan

yes i see it now, and i see how you were left with the answer. your helping me out big time lol

lol awesome ^_^

go for it

1/2(1+sin/cos+cos/1+sin) , what trig function is equal?
Sin
cos
tan
csc
sec
cot

cos/1? you sure, caz that's just cos

yup cos/(1+sin)

oh i see you need to use parenthesis rocco, otherwise there's a lot of miss understandings

ohh im sorry

oh and the first part is (1+sin)/cos

1/2(1+tan+cos+cot))

T-T

i feel quite useless....

give me some time, i'm going to write this out, sorry

no problem, and ure not useless dont worry about that lol

rocco
i have no luck for this one :x
sorry!
repost this one

ok no prob, found another one, wanna take a crack at it, i thnk i got half of it?

rofl sure

ok its csc - cot = 1/ (csc + cot) verify

(csc - cot)(csc + cot) = 1
csc^2 - cot^2 = 1
^-- that's another rule you should remember

ohh but can you cross the = sign when verifying?

i'm not sure i understand what you mean?

yea like that

it's perfectly fine
as i just shown up there LOL
6 is equal to 6
so it's fine
cheers ^_^

ohh i see, haha thanks youve been a big help!!!