help with this equation PLEASE!?

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help with this equation PLEASE!?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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\[y ^{5}-81y=0\]
First factor out a y
I know there are 5 solutions, i'm just not sure exactly what the next steps look like.

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leaving y=0 y^4 - 81 =0
y^4=81 y = +-81^1/4
oh ok, so the other ones would be the same thing but 1/3, 1/3, 1...?
i meant 1/2
hmm fourth root of 81 is 3 3*3*3*3=81 solutions would be 0,3,-3
it says it has 5 solutions
the other 2 would be non-real solutions i believe
if you graph this you will see it only crosses x-axis 3 times
I don't need to graph it I just need to type in the 5 answers. What would the non real solutions be?
ok y^2 +9 =0 y^2 = -9 y = sqrt(-9) = sqrt(9)*i y = +-3i
so 0,-9,\[\sqrt{9}\sqrt{9}\]i, and -3i?
sorry but my online assignment is picky with the format so i want to make sure I type it in correct
oops, just realized i typed it wrong
you are correct y = 0,-3,3,-3i,3i
Oh, because it's the square root of that so this is the final answer.. Gotca, thanks!

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