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anonymous

  • 5 years ago

help with this equation PLEASE!?

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  1. anonymous
    • 5 years ago
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    \[y ^{5}-81y=0\]

  2. dumbcow
    • 5 years ago
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    First factor out a y

  3. anonymous
    • 5 years ago
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    I know there are 5 solutions, i'm just not sure exactly what the next steps look like.

  4. dumbcow
    • 5 years ago
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    leaving y=0 y^4 - 81 =0

  5. dumbcow
    • 5 years ago
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    y^4=81 y = +-81^1/4

  6. anonymous
    • 5 years ago
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    oh ok, so the other ones would be the same thing but 1/3, 1/3, 1...?

  7. anonymous
    • 5 years ago
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    i meant 1/2

  8. dumbcow
    • 5 years ago
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    hmm fourth root of 81 is 3 3*3*3*3=81 solutions would be 0,3,-3

  9. anonymous
    • 5 years ago
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    it says it has 5 solutions

  10. dumbcow
    • 5 years ago
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    the other 2 would be non-real solutions i believe

  11. dumbcow
    • 5 years ago
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    if you graph this you will see it only crosses x-axis 3 times

  12. anonymous
    • 5 years ago
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    I don't need to graph it I just need to type in the 5 answers. What would the non real solutions be?

  13. dumbcow
    • 5 years ago
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    ok y^2 +9 =0 y^2 = -9 y = sqrt(-9) = sqrt(9)*i y = +-3i

  14. anonymous
    • 5 years ago
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    so 0,-9,\[\sqrt{9}\sqrt{9}\]i, and -3i?

  15. anonymous
    • 5 years ago
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    sorry but my online assignment is picky with the format so i want to make sure I type it in correct

  16. anonymous
    • 5 years ago
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    oops, just realized i typed it wrong

  17. dumbcow
    • 5 years ago
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    you are correct y = 0,-3,3,-3i,3i

  18. anonymous
    • 5 years ago
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    Oh, because it's the square root of that so this is the final answer.. Gotca, thanks!

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